15
0
There are 8 10s in 85, with 5 left over.
If s-5=3 then the value of s is 8 !
The perimeter of a regular pentagon is the total length of all its sides, which can be expressed as 5 times the length of one side (s). If the perimeter is given as (10s - 20), we can set up the equation (5s = 10s - 20). Solving for (s), we rearrange the equation to (20 = 10s - 5s), which simplifies to (5s = 20). Thus, (s = 4), meaning each side of the pentagon is 4 units long.
-5
0
s=5 f+s=? Substitute 5 in for s.Substitute 1 in for f.f+s=f+5f=11+5 ={6}
5 = sides of a pentagon(also 5 equals S of a SP means 5 = sides of a square pyramid)
There are 8 10s in 85, with 5 left over.
S = {-5, 1}
If s-5=3 then the value of s is 8 !
50
4/5
-5
5m/s
17
s + 3 = 6s -s -s ------------- 3 = 5s /5 /5 s=3/5 or s=.6