2 , 67 & 134.
1, 2, 3, 4, 6, 12, 67, 134, 201, 268, 402, 804.
The whole-number factors of 804 are 1, 2, 3, 4, 6, 12, 67, 134, 201, 268, 402, and 804.
268% = 268/100 = 217/25
268/1
268 is divisible by 1, 2, 4, 67, 134, 268.
268 is not divisible by 45 without remainder.
268 is divisible by 2, 4, 67, 134, and 268.
268 is divisible by 1, 2, 4, 67, 134, 268.
No.
Yes, 268 is divisible by 2 and 4. To check if a number is divisible by 2, we just need to look at the ones place digit. If it is even, then the number is divisible by 2. In this case, the ones place digit of 268 is 8, which is even, so 268 is divisible by 2. To check if a number is divisible by 4, we need to look at the last two digits of the number. If the last two digits
1, 2, 4, 67, 134, 268
1, 2, 4, 67, 134, 268.
Any of its factors
268, 536, 804 and keep adding 268 forever.
Yes. All even numbers are divisible by two.
Yes. It goes in 67 times.