1
1
tan (30 degrees) would be equal to 0.577350269.
The value of tan 75 degrees can be calculated using the angle sum identity for tangent: tan(75°) = tan(45° + 30°) = (tan 45° + tan 30°) / (1 - tan 45° * tan 30°). Since tan 45° = 1 and tan 30° = 1/√3, substituting these values gives tan 75° = (1 + 1/√3) / (1 - 1/√3) = (√3 + 1) / (√3 - 1). Simplifying this expression results in tan 75° = 2 + √3.
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1.5
1
tan(30)=.5773502692
tan (30 degrees) would be equal to 0.577350269.
tan (30 degrees) would be equal to 0.577350269.
The value of tan 75 degrees can be calculated using the angle sum identity for tangent: tan(75°) = tan(45° + 30°) = (tan 45° + tan 30°) / (1 - tan 45° * tan 30°). Since tan 45° = 1 and tan 30° = 1/√3, substituting these values gives tan 75° = (1 + 1/√3) / (1 - 1/√3) = (√3 + 1) / (√3 - 1). Simplifying this expression results in tan 75° = 2 + √3.
6
Not certain but calculator says 0.577, may have something to do with circle quadrants ie 210 is 30 degrees into third quadrant of circle (tan 30 = 0.577) see google - tan in circle, then scroll to sin, cos, tan
tan(pi/3) = tan (60 degrees) = 1.732 which is square root of 3
1.5
cot(15)=1/tan(15) Let us find tan(15) tan(15)=tan(45-30) tan(a-b) = (tan(a)-tan(b))/(1+tan(a)tan(b)) tan(45-30)= (tan(45)-tan(30))/(1+tan(45)tan(30)) substitute tan(45)=1 and tan(30)=1/√3 into the equation. tan(45-30) = (1- 1/√3) / (1+1/√3) =(√3-1)/(√3+1) The exact value of cot(15) is the reciprocal of the above which is: (√3+1) /(√3-1)
It can be shown that:height = (d tan α tan β)/(tan α - tan β)where: α is the angle closest to the objectβ is the angle further away from the objectd is the distance from the point of angle α to the point of angle βThus: height = (40 ft × tan 50° × tan 30°)/(tan 50° - tan 30°) ≈ 44.80 ft
tangent of 30 degrees = 1/2 of the square root of 3 = roughly 0.5773