It is: 6114/63 = 97 with a remainder of 3
To determine the remainder, you would take 63 and see how many times your divisor fits into it. That will give you a number, which when multiplied by the divisor will be less than 63, and smaller than the divisor. Subtract the result of your divisors times your quotient from 63, and that number is the remainder.
To determine how many times 8 goes into 63, you would perform long division. When you divide 63 by 8, you get 7 with a remainder of 7. This means that 8 goes into 63 a total of 7 times, with a remainder of 7.
13.619
12.6
It is: 6114/63 = 97 with a remainder of 3
To determine the remainder, you would take 63 and see how many times your divisor fits into it. That will give you a number, which when multiplied by the divisor will be less than 63, and smaller than the divisor. Subtract the result of your divisors times your quotient from 63, and that number is the remainder.
141 with remainder 1.
63.8
7.875
63.7143
Because 63 is the smallest positive integer that both of those numbers divide into evenly with no remainder.
To determine how many times 8 goes into 63, you would perform long division. When you divide 63 by 8, you get 7 with a remainder of 7. This means that 8 goes into 63 a total of 7 times, with a remainder of 7.
To find the largest number that, when divided into both 63 and 75, leaves a remainder of three, you can use the concept of greatest common divisor (GCD) or greatest common factor (GCF). The GCD of 63 and 75 is the largest number that can evenly divide both numbers. To find it, you can use the Euclidean algorithm: Start with the two numbers: 63 and 75. Divide 75 by 63: 75 รท 63 = 1 with a remainder of 12. Now, replace the larger number (75) with the remainder (12) and keep the smaller number (63) as is: 63 and 12. Repeat the process: 63 รท 12 = 5 with a remainder of 3. Again, replace the larger number (63) with the remainder (3) and keep the smaller number (12) as is: 12 and 3. Repeat once more: 12 รท 3 = 4 with no remainder. Now that you have reached a point where the remainder is 0, the GCD is the last non-zero remainder, which is 3. So, the largest number that, when divided into both 63 and 75, leaves a remainder of three is 3.
0.0635
Why not use the Euclidean Algorithm and find out? Divide 63 by 25, and you get a remainder of 13. (The quotient is not important.) Now the divisor of the last division problem becomes the dividend, and the remainder becomes the divisor - that is, we divide 25 by 13 this time. We get a remainder of 12. Divide 13 by 12, and you get a remainder of 1. Divide 12 by 1, you get no remainder. Therefore, this last divisor, 1, is the greatest common factor (or divisor) of the original two numbers. (As a side note, because the gcf is 1, that means those two numbers are what's called relatively prime.)
In order for one number to be a factor of another number, it must divide evenly into that number. By dividing 6 into 63, the answer is 10 with 3 remaining. Since there is a remainder, 6 is not a factor of 63.