7-4x = 3
To solve the equation (-74x - 6 - 1 = 0), first combine the constants (-6) and (-1) to get (-74x - 7 = 0). Next, isolate (x) by adding (7) to both sides, resulting in (-74x = 7). Finally, divide both sides by (-74) to find (x = -\frac{7}{74}).
4.7-74x*43h= resolution
mustang 74x
you need to find the value of X first before you can solve this equation
8x - 4x + 7 = 94x + 7 = 94x = 9-74x = 2x = 4/2x = 1/2x = 0.5
If that's 3x2 + 7x + 2, the answer is (x + 2)(3x + 1)
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Let x = first integer2nd integer = x + 13rd integer = x + 2x + (x +1) + (x + 2) = x - 713x + 3 = x - 713x = x - 742x = -74x = -371st Integer = -372nd Integer = -363rd Integer = -35(-37) + (-36) + (-35) = -108-108 + 71 = -37
3/5 + 5x/2 = 8Multiply each term by 53 + 25x/2 = 40Multiply each term by 26 + 25x = 8025x = 80 - 625x = 74x = 74 / 25OR3/5 + 5x/2 = 85x/2 = 8 - 3/55x/2 = 40/5 - 3/55x/2 = 37/55x = 37/5 * 25x = 74/5x = 74/5 * 1/5x = 74/25
Let's represent the two consecutive numbers as x and x+1. The sum of these two numbers is x + (x+1) = 2x + 1. Given that the sum is 75, we have the equation 2x + 1 = 75. Solving for x, we find x = 37. Therefore, the two consecutive numbers are 37 and 38, and their sum is indeed 75.
-x + y = 24x - 3y = -7-x + y = 2 (add x to both sides)y = x + 2 (substitute x + 2 for y into the second equation of the system)4x - 3y = -74x - 3(x + 2) = -7 (solve for x)4x - 3x - 6 = -7x - 6 = -7 (add 6 to both sides)x = -1y = x + 2 (substitute -1 for x)y = -1 + 2y = 1Thus (-1, 1) is the solution of the given system of the equations.
Let the first odd integer be x, so the other consecutive odd integer is x + 2. So we have:x^2 + (x + 2)^2 = 74x^2 + x^2 + 4x + 4 = 742x^2 + 4x + 4 - 74 = 74 - 742x^2 + 4x - 70 = 0 divide by 2 to both sidesx^2 + 2x - 35 = 0(x + 7)(x - 5) = 0x + 7 = 0 or x - 5 = 0x + 7 - 7 = 0 -7 or x - 5 + 5 = 0 + 5x = -7 or x = 5Thus, the first odd integer would be -7 or 5, and the second consecutive odd integer would be -5 (-7 + 2) or 7 (5 + 2).Check: