answersLogoWhite

0

What is 7-4x?

Updated: 10/17/2024
User Avatar

Wiki User

13y ago

Best Answer

7-4x = 3

User Avatar

Alvera Stehr

Lvl 10
3y ago
This answer is:
User Avatar
More answers
User Avatar

Anonymous

Lvl 1
3y ago

-7

This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: What is 7-4x?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

What is best contrast resolution for photo editing?

4.7-74x*43h= resolution


What muscle car does Vin Diesel drive in the Fast and Furious 4?

mustang 74x


What does -7x plus 7 plus -5x plus 3 plus 74x-2 equals?

you need to find the value of X first before you can solve this equation


8x- 4x plus 7 equals 9?

8x - 4x + 7 = 94x + 7 = 94x = 9-74x = 2x = 4/2x = 1/2x = 0.5


Factor the binomial below Enter each factor as a polynomial in descending order3x plus 74x plus 2?

If that's 3x2 + 7x + 2, the answer is (x + 2)(3x + 1)


What is 5 4x-74x?

Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals" etc.


The sum of three consective integers is 71 less than the least of the integers. what is the integers?

Let x = first integer2nd integer = x + 13rd integer = x + 2x + (x +1) + (x + 2) = x - 713x + 3 = x - 713x = x - 742x = -74x = -371st Integer = -372nd Integer = -363rd Integer = -35(-37) + (-36) + (-35) = -108-108 + 71 = -37


How do you solve 3 over 5 plus 5x over 2 equals 8?

3/5 + 5x/2 = 8Multiply each term by 53 + 25x/2 = 40Multiply each term by 26 + 25x = 8025x = 80 - 625x = 74x = 74 / 25OR3/5 + 5x/2 = 85x/2 = 8 - 3/55x/2 = 40/5 - 3/55x/2 = 37/55x = 37/5 * 25x = 74/5x = 74/5 * 1/5x = 74/25


What is the sum of two consecutive numbers is 75?

Let's represent the two consecutive numbers as x and x+1. The sum of these two numbers is x + (x+1) = 2x + 1. Given that the sum is 75, we have the equation 2x + 1 = 75. Solving for x, we find x = 37. Therefore, the two consecutive numbers are 37 and 38, and their sum is indeed 75.


Use the substitution method to solve the system -x plus y equals 2 and 4x-3y equals -7?

-x + y = 24x - 3y = -7-x + y = 2 (add x to both sides)y = x + 2 (substitute x + 2 for y into the second equation of the system)4x - 3y = -74x - 3(x + 2) = -7 (solve for x)4x - 3x - 6 = -7x - 6 = -7 (add 6 to both sides)x = -1y = x + 2 (substitute -1 for x)y = -1 + 2y = 1Thus (-1, 1) is the solution of the given system of the equations.


The sum of the squares of two consecutive odd integers is 74 find the integers?

Let the first odd integer be x, so the other consecutive odd integer is x + 2. So we have:x^2 + (x + 2)^2 = 74x^2 + x^2 + 4x + 4 = 742x^2 + 4x + 4 - 74 = 74 - 742x^2 + 4x - 70 = 0 divide by 2 to both sidesx^2 + 2x - 35 = 0(x + 7)(x - 5) = 0x + 7 = 0 or x - 5 = 0x + 7 - 7 = 0 -7 or x - 5 + 5 = 0 + 5x = -7 or x = 5Thus, the first odd integer would be -7 or 5, and the second consecutive odd integer would be -5 (-7 + 2) or 7 (5 + 2).Check:


How do you solve an equation by factoring?

In the special case when a =1, the factoring method results in finding 2 NUMBERS knowing their sum and their product. The process is simple. However, when the constants a, b, c are large numbers, and contain themselves many factors, then the factoring method becomes complicated and takes long time in the process. For examples, solving these equations by the factoring method will take lot of time because of the high number of permutations: (6x^2 - 11x - 35 = 0) ; (45x^2 + 74x - 55 = 0) ; (45x^2 - 152x - 36 = 0); (12x^2 + 5x - 72 = 0) There is a new method, called Diagonal Sum Method, that can quickly and directly give the 2 roots, WITHOUT HAVING TO FACTOR THE EQUATION. The innovative concept of the new method is finding 2 FRACTIONS knowing their sum (-b/a) and their product (c/a). It is faster, more convenient than the factoring method since it requires fewer permutations by using the rule of signs for real roots. It is applicable whenever the equation can be factored. So, I advise you to proceed solving any quadratic equation in 2 steps. First step, use the Diagonal Sum method to solve it. It usually takes fewer than 3 trials. If it fails, then the quadratic formula must be used in second step. See book title:" New method for solving quadratic equations and inequalities" (Trafford Publishing 2009)