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7-4x = 3
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How do you solve the equation -74x-6-1?
To solve the equation (-74x - 6 - 1 = 0), first combine the constants (-6) and (-1) to get (-74x - 7 = 0). Next, isolate (x) by adding (7) to both sides, resulting in (-74x = 7). Finally, divide both sides by (-74) to find (x = -\frac{7}{74}).
What is best contrast resolution for photo editing?
4.7-74x*43h= resolution
What muscle car does Vin Diesel drive in the Fast and Furious 4?
mustang 74x
What does -7x plus 7 plus -5x plus 3 plus 74x-2 equals?
you need to find the value of X first before you can solve this equation
8x- 4x plus 7 equals 9?
8x - 4x + 7 = 94x + 7 = 94x = 9-74x = 2x = 4/2x = 1/2x = 0.5
Factor the binomial below Enter each factor as a polynomial in descending order3x plus 74x plus 2?
If that's 3x2 + 7x + 2, the answer is (x + 2)(3x + 1)
What is 5 4x-74x?
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The sum of three consective integers is 71 less than the least of the integers. what is the integers?
Let x = first integer2nd integer = x + 13rd integer = x + 2x + (x +1) + (x + 2) = x - 713x + 3 = x - 713x = x - 742x = -74x = -371st Integer = -372nd Integer = -363rd Integer = -35(-37) + (-36) + (-35) = -108-108 + 71 = -37
How do you solve 3 over 5 plus 5x over 2 equals 8?
3/5 + 5x/2 = 8Multiply each term by 53 + 25x/2 = 40Multiply each term by 26 + 25x = 8025x = 80 - 625x = 74x = 74 / 25OR3/5 + 5x/2 = 85x/2 = 8 - 3/55x/2 = 40/5 - 3/55x/2 = 37/55x = 37/5 * 25x = 74/5x = 74/5 * 1/5x = 74/25
What is the sum of two consecutive numbers is 75?
Let's represent the two consecutive numbers as x and x+1. The sum of these two numbers is x + (x+1) = 2x + 1. Given that the sum is 75, we have the equation 2x + 1 = 75. Solving for x, we find x = 37. Therefore, the two consecutive numbers are 37 and 38, and their sum is indeed 75.
Use the substitution method to solve the system -x plus y equals 2 and 4x-3y equals -7?
-x + y = 24x - 3y = -7-x + y = 2 (add x to both sides)y = x + 2 (substitute x + 2 for y into the second equation of the system)4x - 3y = -74x - 3(x + 2) = -7 (solve for x)4x - 3x - 6 = -7x - 6 = -7 (add 6 to both sides)x = -1y = x + 2 (substitute -1 for x)y = -1 + 2y = 1Thus (-1, 1) is the solution of the given system of the equations.
The sum of the squares of two consecutive odd integers is 74 find the integers?
Let the first odd integer be x, so the other consecutive odd integer is x + 2. So we have:x^2 + (x + 2)^2 = 74x^2 + x^2 + 4x + 4 = 742x^2 + 4x + 4 - 74 = 74 - 742x^2 + 4x - 70 = 0 divide by 2 to both sidesx^2 + 2x - 35 = 0(x + 7)(x - 5) = 0x + 7 = 0 or x - 5 = 0x + 7 - 7 = 0 -7 or x - 5 + 5 = 0 + 5x = -7 or x = 5Thus, the first odd integer would be -7 or 5, and the second consecutive odd integer would be -5 (-7 + 2) or 7 (5 + 2).Check:
