1
8
81
16
64 8*8=64 2^6=64
No, 2 is neither a perfect square nor a perfect cube.
128 is neither a perfect square nor a perfect cube, it is 2⁷ (2 to the 7th power).
To be a perfect square, a number must have a square root that evaluates to an integer. The square root of 2 is approximately equal to 1.414, thus it is not a perfect square.
2 is prime, its only factors are one and itself.
To be a perfect square, all the primes in a number's prime factorisation must have an even power To be a perfect cube, all the primes in a number's prime factorisation must a power that is a multiple of 3 → To be a perfect square, all the primes in a number's prime factorisation must a power that is a multiple of 3 and a multiple of 2, ie the power must be a multiple of 6 The smallest prime is 2 2⁶ = 64 = (2³)² = 8² = (2²)³ = 4³ 2¹² = 4096 (too large) 3⁶ = 729 (too large) There is also 1 = 1² = 1³ Thus the whole numbers less than 100 which are both perfect squares and perfect cubes are 1 and 64.
The product of two perfect squares is always a perfect square because a perfect square can be expressed as the square of an integer. If we take two perfect squares, say ( a^2 ) and ( b^2 ), their product can be written as ( a^2 \times b^2 = (a \times b)^2 ). Since ( a \times b ) is an integer, ( (a \times b)^2 ) is also a perfect square, confirming that the product of two perfect squares yields another perfect square.
No. Though every perfect square is a rational number, not every rational number is a perfect square. Example: 2 is a rational number but sqrt(2) is not rational, so 2 is not a perfect square.
It is not possible for a perfect square to have just 2 terms.