To be divisible by 3, 9, 5 and 10, a number must be a multiple of their lowest common multiple.
lcm(3, 9, 5, 10) = 90
So all multiples of 90 are divisible by 3, 9 5, and 10.
The first 4 digit number (excluding leading zeros) is 1000
→ 1000 ÷ 90 = 111/9 → first multiple of 90 ≥ 1000 is 12 x 90 = 1080
The last 4 digit number is 9999
→ 9999 ÷ 90 = 1111/10 → last multiple of 90 ≤ 9999 is 111 x 90 = 9990
→ all multiples of 90 between 12 and 11 (inclusive) are 4 digit numbers divisible by 3, 9, 5, 10, namely:
1080, 1170, 1260, 1350, 1440, 1530, 1620, 1710, 1800, 1890, 1980, 2070, 2160, 2250, 2340, 2430, 2520, 2610, 2700, 2790, 2880, 2970, 3060, 3150, 3240, 3330, 3420, 3510, 3600, 3690, 3780, 3870, 3960, 4050, 4140, 4230, 4320, 4410, 4500, 4590, 4680, 4770, 4860, 4950, 5040, 5130, 5220, 5310, 5400, 5490, 5580, 5670, 5760, 5850, 5940, 6030, 6120, 6210, 6300, 6390, 6480, 6570, 6660, 6750, 6840, 6930, 7020, 7110, 7200, 7290, 7380, 7470, 7560, 7650, 7740, 7830, 7920, 8010, 8100, 8190, 8280, 8370, 8460, 8550, 8640, 8730, 8820, 8910, 9000, 9090, 9180, 9270, 9360, 9450, 9540, 9630, 9720, 9810, 9900, 9990
There is no 5 digit number which is divisible by 23456910 (an 8-digit number)..
A three digit number cannot be divisible by a 5 digit number - in any base.
4500
305 can only be [exactly] divided by 5 and not 2, 3, 6, 9 nor 10.Divisibility tests:2: NoNumber must be even (last digit divisible by 2). Last digit is 5 which is not even, so the whole number (305) not divisible by 2.3: NoAdd up the digits of the number; if this sum is divisible by 3, then the original number is divisible by 3: 3 + 0 + 5 = 8 which is not divisible by 3, so the original number (305) is not divisible by 3.5: YesLast digit is 0 or 5. Last digit is 5, so 305 is divisible by 5. 6: No6 = 2 x 3, so number must pass both tests for divisibility of 2 and 3; 305 fails tests for (both) 2 and 3 (above), so is not divisible by 6. 9: NoAdd up the digits of the number; if this sum is divisible by 9, then the original number is divisible by 9: 3 + 0 + 5 = 8 which is not divisible by 9, so the original number (305) is not divisible by 9.10: NoThe last digit of the number must be 0. Last digit is 5, so 305 is not divisible by 10.
36360 is a 5 digit number that is divisible by both 3 and 9.
You know a number is divisible by five when its last digit has either a 5 or 0.
Any number that ends with the digit 5 is divisible by 5.Any number that ends with the digit 5 is divisible by 5.Any number that ends with the digit 5 is divisible by 5.Any number that ends with the digit 5 is divisible by 5.
There is no 5 digit number which is divisible by 23456910 (an 8-digit number)..
If the last digit is 0 or 5 then the number is divisible by 5. Last digit of 745 is 5 so, 745 is divisible by 5.
There are 18 numbers with 2 digits that are divisible by 5. First 2 digit number is 10 → 10 ÷ 5 = 2 → first 2 digit number divisible by 25 is 5 × 2 Last 2 digit number is 99 → 99 ÷ 5 = 19 4/5 → last 2 digit number divisible by 5 is 5 × 19 → There are 19 - 2 + 1 = 18 numbers with 2 digit divisible by 5.
what is the largest three-digit number that is divisible by 4, 5, and 6
No, 1017 is not divisible by 5. A number is divisible by 5 only if its last digit is 0 or 5. Since the last digit of 1017 is 7, it is not divisible by 5
There can be no such number. If it is divisible by 5 and 6it must be divisible by 6.
To find if a number is divisible by 5, the digit in the ones place has to be 0 or 5.
Yes, 450 is divisible by 5. A number is divisible by 5 if its last digit is 0 or 5. In this case, the last digit of 450 is 0, so it is divisible by 5.
The least three-digit number that is divisible by both 5 and 9 is 135.
to be divisible by 5 the last digit of the number has to be 0 or 5