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What is the opposite of a supplementary angle?
Y is a supplementary angle to angle X if X + Y = 180 degrees. The only opposite to X + Y = 180 is X + Y ≠180. Such an angle has no specific name.
Is a suplementary angle 180 degrees?
the angle and its supplementary angle added together is 180 the supplementary angle of angle y is 180-y
How do you find angles of a triangle with a given slopes?
Slope = Rise/Run = y/x 1. leg = rise = y 2. leg = run = x 3. hypotenuse = √(x^2 + y^2) tan (angle 1) = x/y angle 1 = arctan(x/y) tan (angle 2) = y/x angle 2 = arctan(y/x)
How do you find the missing side of a triangle?
The most common way is to use Pythagoras' principle; "A2 + B2 = C2", where C is the side you are trying to find out and the other two are the lengths you already have. In this situation, C is the Hypotenuse, or the longest side of the triangle. When finding the shortest side, you have to rearrange the equation.However, this is only useful for Right Angled triangles. It is possible to change this to "A2 = B2 + C2 - (2BC)cos'a'", where A is the side you are looking for, and 'a' is the angle OPPOSITE this side. B and C remain the two given sides.Assuming you have a right triangle (one angle is 90o), we can use either the Pythagorean Theorem or the trigonometric functions.Let's assume your base is "x", height "y" and diagonal (hypotenuse) "r".Finding Values (Pythagorean Theorem):The Pythagorean Theorem states that, for a right triangle, r^2 = x^2 + y^2. We can use a little bit of algebra to find x, y and r.r = sqrt(x^2 + y^2)r^2 = x^2 + y^2r = sqrt(x^2 + y^2); remove the ^2 from rx = sqrt(r^2 - y^2)r^2 = x^2 + y^2r^2 - y^2 = x^2; move y^2 to the left side of the equationsqrt(r^2 - y^2) = x; remove the ^2 from xy = sqrt(r^2 - x^2)r^2 = x^2 + y^2r^2 - x^2 = y^2; move x^2 to the left side of the equationsqrt(r^2 - x^2) = y; remove the ^2 from yFinding Values (Trigonometric Functions):Acquiring Ratios:cos(angle) = x/rsin(angle) = y/rtan(angle) = y/xAcquiring Angles:cos-1(x/r) = anglesin-1(y/r) = angletan-1(y/x) = angleThat looks confusing. What are cos, sin, tan, etc?They're functions. You give a function input and it outputs something else. We won't worry about what they actually "are" - answering that requires calculus.x = cos(angle) * rcos(angle) = x/rcos(angle) * r = x; move r to the left side of the equationy = sin(angle) * rsin(angle) = y/rsin(angle) * r = y; move r to the left side of the equationx = 1 / (tan(angle)/y)tan(angle) = y/xtan(angle) / y = 1/x; move y to the left side of the equation1 / (tan(angle) / y) = x; flip the equationy = tan(angle) * xtan(angle) = y/xtan(angle) * x = y; move x to the left side of the equationr = 1 / (cos(angle)/x)cos(angle) = x/rcos(angle) / x = 1/r; move x to the left side of the equation1 / (cos(angle)/x) = r; flip the equationr = 1 / (sin(angle)/y)sin(angle) = y/rsin(angle) / y = 1/r; move y to the left side of the equation1 / (sin(angle)/y) = r; flip the equationI hope this helps,- Pritchard
What is the slope and y-intercept of y equals -2x plus 5?
y = -2x + 5 Slope is -2, that is the angle the line makes with the x-axis is such that tangent of that angle is -2 The y-intercept is 5
∠angle, x, and \angle y∠angle, y are supplementary angles. \angle y∠angle, y measures 156^\circ156 What is the measure of \angle x∠xangle, x∘ 156?
for a book cover is this good
What is the opposite of a supplementary angle?
Y is a supplementary angle to angle X if X + Y = 180 degrees. The only opposite to X + Y = 180 is X + Y ≠180. Such an angle has no specific name.
Is a suplementary angle 180 degrees?
the angle and its supplementary angle added together is 180 the supplementary angle of angle y is 180-y
If the supplement of angle Y is 75 then what is the measure of angle Y?
105 degrees
What is the third angle of a right triangle if one of the angles measures Y?
If Y is the right angle then the third angle is indeterminate. Otherwise it is 90 - Y degrees.
How do you solve if angle x and angle y are complementary and angle z and angle q are complementary and angle x and angle z are congruent then angle y is congruent to angle q?
x and y are complementary so x + y = 90 and so y = 90 - x z and q are complementary so z + q = 90 and so q = 90 - z x = z so 90 - x = 90 - z that is y = q
What angle is quarter times greater than its supplementary angle?
Angle 100° is quarter times greater than its supplementary angle 80°. Solution: let 'x' be the required angle and 'y' be its complementary angle. x+y=180° Now, x is quarter times greater than y. That is, x=y+¼y. therefore x=y+0.25y =1.25y thus, 1.25y + y = 180° 2.25y = 180° y=80° thus, x=1.25 X 80 =100°
What is the Symmetric Property of Congruence?
The Symmetric Property of Congruence: If angle A is congruent to angle B, then angle B is congruent to angle A. If X is congruent to Y then Y is congruent to X.
Transitive property of congruence if a congruence x and t Then?
If angle A is congruent to angle B, then angle B is congruent to angle A.If X is congruent to Y then Y is congruent to X.
How do you find angles of a triangle with a given slopes?
Slope = Rise/Run = y/x 1. leg = rise = y 2. leg = run = x 3. hypotenuse = √(x^2 + y^2) tan (angle 1) = x/y angle 1 = arctan(x/y) tan (angle 2) = y/x angle 2 = arctan(y/x)
What else would need to congruent to show that abc is congruent to xyz by asa?
angle B angle Y (Tested, correct) Nicki is not the answer, just ignore that.
How do you find the side length of a triangle?
The most popular triangle used in construction, engineering and mathematics is the right triangle, which has a 90o angle at the base. We'll call your base "x", height "y" and diagonal (hypotenuse) "r".You can find these values using your calculator's trigonometric functions, or you can use the Pythagorean Theorem.Finding Values (Pythagorean Theorem):The Pythagorean Theorem is straightforward and states that, for a right triangle, r^2 = x^2 + y^2. We can use a little bit of algebra to find x, y and r.r = sqrt(x^2 + y^2)r^2 = x^2 + y^2r = sqrt(x^2 + y^2); remove the ^2 from rx = sqrt(r^2 - y^2)r^2 = x^2 + y^2r^2 - y^2 = x^2; move y^2 to the left side of the equationsqrt(r^2 - y^2) = x; remove the ^2 from xy = sqrt(r^2 - x^2)r^2 = x^2 + y^2r^2 - x^2 = y^2; move x^2 to the left side of the equationsqrt(r^2 - x^2) = y; remove the ^2 from yFinding Values (Trigonometric Functions):Acquiring Ratios:cos(angle) = x/rsin(angle) = y/rtan(angle) = y/xAcquiring Angles:cos-1(x/r) = anglesin-1(y/r) = angletan-1(y/x) = angleThat looks confusing. What are cos, sin, tan, etc?They're functions. You give a function input and it outputs something else. How they do this is complicated and required calculus.x = cos(angle) * rcos(angle) = x/rcos(angle) * r = x; move r to the left side of the equationy = sin(angle) * rsin(angle) = y/rsin(angle) * r = y; move r to the left side of the equationx = 1 / (tan(angle)/y)tan(angle) = y/xtan(angle) / y = 1/x; move y to the left side of the equation1 / (tan(angle) / y) = x; flip the equationy = tan(angle) * xtan(angle) = y/xtan(angle) * x = y; move x to the left side of the equationr = 1 / (cos(angle)/x)cos(angle) = x/rcos(angle) / x = 1/r; move x to the left side of the equation1 / (cos(angle)/x) = r; flip the equationr = 1 / (sin(angle)/y)sin(angle) = y/rsin(angle) / y = 1/r; move y to the left side of the equation1 / (sin(angle)/y) = r; flip the equation
