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An N3 certificate requires a minimum of four passed technical subjects. N3 subjects are at a level of Matric. N3 certificate must have an addition of two languages to be fully equivalent to a Matric certification.
6+N3 is the sum of N*3 then you add six. 6*N3 is you multiply 6 times three times N times three.
Input N1, N2, N3 Max = N1 If N2 > Max then Max = N2 If N3 > Max then Max = N3 Display Max
The sequence is too short for a definitive answer. One possibility is Un = n2 - 2n + 2 for n = 1, 2, 3, ... another is Un = (n3 - n + 6)/6 or Un = (n3 - 3n2 + 5)/3 There are many more.
n3 + 3n2 + 4n + 12 = (n3 + 3n2) + (4n + 12) = n2(n + 3) + 4(n + 3) = (n2 + 4)(n + 3).