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2.5
If it is parallel, it must have the same slope of the original line which is -5.
y = -5x + 9 is the equation of a straight line. It cannot be parallel or perpendicular by itself, you need another line to compare it to.
y=5xx2+y2=26Substitute the first equation into the second for y.x2 + (5x)2 = 26x2 + 25x2 = 2626x2 = 26x2 = 1x = SQRT(1) = 1 & -1y = 5*1 = 5y = 5*-1 = -5So the solutions are: (1,5) & (-1, -5)
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