When you divide 24 by 7 the remainder is 3.
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Prime Factor tree of 63. We note that '63' is an odd number , because it does NOT end in 0,2,4,6,8 So it will not divide by ;2 So we try the next prime number, which is '3' 3)63 = 21 Keep on dividing by '3' until it will not divide any further by '3' 3)21 = 7 Since '3' will not divide into '7' and '7' is a prime number, divide '7' into itself , to reduce to '1' 7)7 = 1 So the prime factor tree/stepladder of '63' is 3,3,7. This can be expressed as 3^(2) x 7^(1) = 3^(2) x 7 .
3
7 minus the product of v and 3
4. Reverse the process to find the number: 7 is added to the product of 3 and a number to get 19. The last thing done is add 7; the reverse process of add is subtract, so subtract 7, leaving: The product of 3 and a number is 19 - 7 = 12. The reverse process to multiply (product) by 3 is divide, so divide by 3, leaving: a number is 12 ÷ 3 = 4
When you divide 24 by 7 the remainder is 3.
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No.
Meaningless question. I would guess that the questioner has typed 'product' when he means 'remainder'.
Prime Factor tree of 63. We note that '63' is an odd number , because it does NOT end in 0,2,4,6,8 So it will not divide by ;2 So we try the next prime number, which is '3' 3)63 = 21 Keep on dividing by '3' until it will not divide any further by '3' 3)21 = 7 Since '3' will not divide into '7' and '7' is a prime number, divide '7' into itself , to reduce to '1' 7)7 = 1 So the prime factor tree/stepladder of '63' is 3,3,7. This can be expressed as 3^(2) x 7^(1) = 3^(2) x 7 .
3
7 minus the product of v and 3
The product of 3 and 7 is 21
3/7 = 0.428571428571428
63 is NOT an even number, it is an an odd number, because it does NOT end in 0,2,4,6,8. Therefore it will NOT divide by '2'. So try the next prime number , which is '3' 3)63 = 3)21 = 7)7 = 1 When reduced to '1' , all the primes are factors. Hence 3 x 3 x 7 = 3^(2) x 7^(1) = 3^(2) x 7 Done!!!!!
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