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What is 3 times 3 square root 2?
3(3 square root of 2) = 9(square root of 2)
What is 3 root of 2 and the root of 2?
The cubed root of 2, or 21/3, is equal to 1.259921 The square root of 2, or 21/2, is equal to 1.414214
What is the square root of 3 divided by 2 plus the square root of 3 divided by 2?
2 times the Square root of 3 + 4
Square root of 12 over the square root of 4?
2 root 3 over 2, so square root of 3
What is the cube root of 2 an 3?
The cube root of 2 is 1.2599210498948732 (rounded).The cube root of 3 is 1.4422495703074083 (rounded).
What is 3 times 3 square root 2?
3(3 square root of 2) = 9(square root of 2)
Can 2 divided by 2 square root 3 be simplified?
Yes, the expression 2 divided by 2 square root 3 can be simplified. To simplify this expression, we need to rationalize the denominator. Multiplying both the numerator and the denominator by the conjugate of the denominator (2 square root 3), we get (2 * 2 square root 3) / (2 * 2 square root 3 * 2 square root 3). This simplifies to 4 square root 3 / 12, which further simplifies to square root 3 / 3.
What is 3 root 2 plus 2 root 2?
5 root 2
Simplify the square root of 8 multiplied by the square root of 18?
root 8 = root 4 x root 2 = 2 root 2, root 18 = root 9 x root 2 = 3 root 2; 2 root 2 x 3 root 2 = 6 x 2 = 12
What is 3 root of 2 and the root of 2?
The cubed root of 2, or 21/3, is equal to 1.259921 The square root of 2, or 21/2, is equal to 1.414214
2 - root 3 by root 3?
-1
Square root 2 times square root 3 times square root 8?
square root 2 times square root 3 times square root 8
What is the square root of 3 divided by 2 plus the square root of 3 divided by 2?
2 times the Square root of 3 + 4
What is Square root of 3 plus square root of 3?
It is 2*square root of 3 or approximately 3.464101615.
What is sin cos tan csc sec cot of 30 45 60 degrees?
Sin(30) = 1/2 Sin(45) = root(2)/2 Sin(60) = root(3)/2 Cos(30) = root(3)/2 Cos(45) = root(2)/2 Cos(60) = 1/2 Tan(30) = root(3)/3 Tan(45) = 1 Tan(60) = root(3) Csc(30) = 2 Csc(45) = root(2) Csc(60) = 2root(3)/3 Sec(30) = 2root(3)/3 Sec(45) = root(2) Sec(60) = 2 Cot(30) = root(3) Cot(45) = 1 Cot(60) = root(3)/3
Square root of 12 over the square root of 4?
2 root 3 over 2, so square root of 3
Find the two numbers whose product is 1 and whose sum is 1?
x + y = 1xy = 1y = 1 - xx(1 - x) = 1x - x^2 = 1-x^2 + x - 1 = 0 or multiplying all terms by -1;(-x^2)(-1) + (x)(-1) - (1)(-1) = 0x^2 - x + 1 = 0The roots are complex numbers. Use the quadratic formula and find them:a = 1, b = -1, and c = 1x = [-b + square root of (b^2 - (4)(a)(c)]/2a orx = [-b - square root of (b^2 - (4)(a)(c)]/2aSox = [-(-1) + square root of ((-1)^2 - (4)(1)(1)]/2(1)x = [1 + square root of (1 - 4]/2x = [1 + square root of (- 3)]/2 orx = [1 + square root of (-1 )(3)]/2; substitute (-1) = i^2;x = [1 + square root of (i^2 )(3)]/2x = [1 + (square root of 3)i]/2x = 1/2 + [i(square root of 3]/2 andx = 1/2 - [i(square root of 3)]/2Since we have two values for x, we will find also two values for yy = 1 - xy = 1 - [1/2 + (i(square root of 3))/2]y = 1 - 1/2 - [i(square root of 3)]/2y = 1/2 - [i(square root of 3)]/2 andy = 1 - [1/2 - (i(square root of 3))/2)]y = 1 - 1/2 + [i(square root of 3))/2]y = 1/2 + [i(square root of 3)]/2Thus, these numbers are:1. x = 1/2 + [i(square root of 3)]/2 and y = 1/2 - [i(square root of 3)]/22. x = 1/2 - [i(square root of 3)]/2 and y = 1/2 + [i(square root of 3)]/2Let's check this:x + y = 11/2 + [i(square root of 3)]/2 +1/2 - [i(square root of 3)]/2 = 1/2 + 1/2 = 1xy = 1[1/2 + [i(square root of 3)]/2] [1/2 - [i(square root of 3)]/2]= (1/2)(1/2) -(1/2)[i(square root of 3)]/2] + [i(square root of 3)]/2](1/2) - [i(square root of 3)]/2] [i(square root of 3)]/2]= 1/4 - [i(square root of 3)]/4 + [i(square root of 3)]/4 - (3i^2)/4; substitute ( i^2)=-1:= 1/4 - [(3)(-1)]/4= 1/4 + 3/4= 4/4=1In the same way we check and two other values of x and y.
