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What else can I help you with?
X4 plus y4 divided by x plus y?
(x4 + y4)/(x + y) = Quotient = x3 - x2y + xy2 - y3 Remainder = - 2y4/(x+y) So, x3 - x2y + xy2 - y3 - 2y4/(x+y)
What is y to the 8th power as an product in four different was with only positive exponents?
y6 x y2 y4 x y4 y2 x y2 x y4 y2 x y2 x y2 x y2
X2 plus y4 plus x4 plus y2?
x2 + y4 + x4 +y2 = x6 + y6unless you know what x and y are.* * * * *x2 + y4 + x4 + y2 ??I don't believe that this expression can be factorised or otherwise simplified.It certainly does not equal x6 + y6,for all x and all y:for example, if x = y = 1, thenx2 + y4 + x4 + y2 = 4, whilstx6 + y6 = 2;thus, they are two manifestly unequal quantities.
What values do x and y have if x16 y16 and when x and y are combined they equal 0?
If ( x = 16 ) and ( y = -16 ), then their combination ( x + y = 0 ) holds true. Thus, the values of ( x ) and ( y ) are 16 and -16, respectively.
What is y plus y plus y plus y?
y4.
Can you completely factor x32 - y32?
0
How can you do x4-y4?
(x2 + y2)(x + y)(x - y) = x4 - y4.
How do you Evaluate the expression X2 and y4?
It is x*x + y*y*y*y
X 2 y19 X-Y4?
X+2 Y=19 X-Y=4
What is Y4 x Y-3?
7
X4 plus y4 divided by x plus y?
(x4 + y4)/(x + y) = Quotient = x3 - x2y + xy2 - y3 Remainder = - 2y4/(x+y) So, x3 - x2y + xy2 - y3 - 2y4/(x+y)
What is y to the 8th power as an product in four different was with only positive exponents?
y6 x y2 y4 x y4 y2 x y2 x y4 y2 x y2 x y2 x y2
What is x-7 y4?
x-7*y*4 >> solve it * is multiply-
(4x-y) plus (-10 plus y) if x3 and y4?
If x = 3 and y = 4 then the answer is 2
What is y plus y4?
y + y4 = y5 , possibly. Except that conventionally, the number (or coefficient) would be written first. y + y4 = y*(1 + y3) = y(1 + y)*(1 - y + y2)
What is 4x-y4 what is the value of y?
4x-y4 what = 0
What is the answer for x plus y to 4th power?
(x+y)4 = (x2+2xy+y2)2 = x4+4x3y+6x2y2+4xy3+y4
