Diagonal = 17 cm and height = 8 cm
so Length = sqrt[172 - 82] = sqrt(225) = 15 cm
Then area = length*height = 15*8 = 120 cm2
In a rhombus, the length of the side opposite a side with length 736
Using Pythagoras' theorem it works out as 194.9820505 or 195 centimeters
To find the length of a diagonal in a rectangle, use the Pythagorean method. Diagonal length = square root(length squared + height squared).
If d is the diagonal and h is the height Let, l=length of rectangle we have By pythagrous theorem d square= l square + h square therefore l square= d square - h square
area of rectangle = base x height = 9 x 10 = 90 square cms
If you mean a rectangle, just multiply the length times the height. If (for example) length and height are in centimeters, then the area is in square centimeters. Similar for other units.
15 cm for the diagonal.
Using Pythagoras' theorem it works out as 194.9820505 or 195 centimeters
To find the length of a diagonal in a rectangle, use the Pythagorean method. Diagonal length = square root(length squared + height squared).
If d is the diagonal and h is the height Let, l=length of rectangle we have By pythagrous theorem d square= l square + h square therefore l square= d square - h square
area of rectangle = base x height = 9 x 10 = 90 square cms
If you mean a rectangle, just multiply the length times the height. If (for example) length and height are in centimeters, then the area is in square centimeters. Similar for other units.
The diagonal is 7.21 feet.
Area = length * height. A = 20cm * 12cm A = 240 cm2
The length of the diagonal is about 16.03 feet.
The area of a rectangle is simply length x width. If the measurements are in centimeters, then the area will come out in square centimeters.
If it's a rectangle and you know its length and height then use Pythagoras' theorem to find the length of its diagonal
The one alternative to find the area of a rectangle is when you are given the length of one diagonal and its slope.