If it's a rectangle and you know its length and height then use Pythagoras' theorem to find the length of its diagonal
It depends on what the measure of 11 metres represents: the length of a side, the length of the diagonal or something else.
The diagonal length of a square with a 900 square foot area is: 42.43 feet.
Using Pythagoras: diagonal² = side² + side² = 2 × side² → side² = diagonal² ÷ 2 area = side² = diagonal² ÷ 2 → diagonal² = 2 × area → diagonal = √(2 × area) = √(2 × 36) = 6√2 ≈ 8.49
it is impossible for a diagonal of a rhombus to be the same length as its perimeter
The answer to this question depends on what characteristic of a rhombus you are measuring: the length of its sides, its perimeter, area, length of diagonal, its acute angles, its obtuse angles, or something else.
The length of a square with an area of 81 would be 9.
The diagonal is 14 inches.
The diagonal will be 8.66 cm
The square's diagonal is 11.314 cm
The answer depends on which characteristic you wish to measure: its diameter, volume, mass, weight, etc.
The answer will depend on what 640 is meant to measure: area, perimeter, length of diagonal. Who knows? Especially when no units are given. It is, therefore, impossible to give a sensible answer to this question.
If the area of a square is 100, then its side length is 10. If we draw in a diagonal, then we know by the Pythagorean formula that the diagonal's length is sqrt(10^2 + 10^2) = sqrt(200) = 10*sqrt(2).The square root of 2 is approximately 1.414, so the diagonal's length is approximately 10*1.414 =14.14* The diagonal of any square is the side length times (sq rt 2).