7
Area of a rectangle is length x width. It isn't clear what the width is in this case - or how you could solve for it.
a rectangle
To find the width of the rectangle, we start with the area formula: Area = Length × Width. Given that the area is (8w + 18) square feet and the length is 2 feet, we can set up the equation: [ 2 \times \text{Width} = 8w + 18. ] Dividing both sides by 2 gives us the width expression: [ \text{Width} = 4w + 9. ] Thus, the expression for the width of the rectangle is (4w + 9).
6x2+19x+10 = (2x+5)(3x+2) Length = 2x+5 Width = 3x+2
Perimeter: (2*L)+(2*W) [length times two plus width times two] Area: L*W [length times width]
The area is the length times the width. The perimeter is two times the length plus two times the width.
The area is the length times the width. The perimeter is two times the length plus two times the width.
56
The area is the length times the width. The perimeter is two times the length plus two times the width.
Area of a rectangle is length x width. It isn't clear what the width is in this case - or how you could solve for it.
Perimeter: Add the length of the four sides. Area: Multiply length x width.
a rectangle
2 times length plus 2 times width = perimeterhalf the perimeter of a rectangle
To find the width of the rectangle, we start with the area formula: Area = Length × Width. Given that the area is (8w + 18) square feet and the length is 2 feet, we can set up the equation: [ 2 \times \text{Width} = 8w + 18. ] Dividing both sides by 2 gives us the width expression: [ \text{Width} = 4w + 9. ] Thus, the expression for the width of the rectangle is (4w + 9).
6x2+19x+10 = (2x+5)(3x+2) Length = 2x+5 Width = 3x+2
Perimeter: (2*L)+(2*W) [length times two plus width times two] Area: L*W [length times width]
For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.