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Q: What is the area of a square with a side length of 3x?

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The area of square is : 9.0

The square is formed from a wire the length of 3x, which forms a perimeter of the same length. Because each side of the square is one fourth of the total perimeter (1 out of 4 equal sides), each side is 3x/4. The square of one side of a square is equal to the area of that square, so the area is (3x/4)2 = (9/16)x2.The answer is then A = (9/16)x2.

2

the length of a side is x. (3x)(x)

If the other side is x metres, then the area is 3*x = 3x sq metres. So 3x = 18 and so x = 6 metres.

7

We have to assume that this rectangle is a square as only one side's length is provided so 3X 3 = 9 cm^2

9x^2 + 6x + 1

-1

I think it's 12x square.

x^2=3x(x-2)

Let x be the width of the rectangle. Then the length is 3x. The area of the rectangle is 3x * x = 3x^2, which also has to be 48. Solving for x, we get that the width is 4, and the length is 12.

6*(the area of one side) 6*(3x*3x) 6*(9x2) 54x2

Length = 3x - 2Width = x + 4Area = (length) times (width) = (3x - 2) (x + 4) = 3x2 + 10x - 8

If we express the shortest side as x, then the rectangle's length is 3x (as it is 3 times as long as its width).To find the area multiply the length and witdh together.x * 3x = 3x2The area of the rectangle would be 3x2.e.g if the width of the rectangle was 4, the area would be:3 x 42 = 48

It will be (3x+2)*n whereas n is the number of its sides

Quadratic equation: 9x2-21x+12.25 = 0 Area: 36.75 square cm

Find the area of a floor with width 4x+2 and length 3x-5

6x2+19x+10 = (2x+5)(3x+2) Length = 2x+5 Width = 3x+2

Let the width be equal to x. The width is one-third the length, so the length is three times the width or 3x. The area is 48, so then 3x times x =48, or 3x squared = 48. x^2 then equals 48/3 or 16, so x =4. So the rectangle is 4 x 12 cm.

Area = length x wide = x(3x + 1) = 30x(3x + 1) = 303x2 + x = 303x2 + x - 30 = 0(3x + 10)(x - 3) = 03x + 10 = 0 or x - 3 = 0x = -10/3 = -3 1/3 or x = 3

Area of one side - 3x x 3x=9x2cm2 A cube has 6 sides Therefore 6 x 9x2 =54x2cm2

'x' is equal to 8 feet. The length would be (3*8)+8= 32'.

Let the length be 3x and the width be x: 3x*x = 243 3x2 = 243 Divide both sides by 3: x2 = 81 Square root both sides: x = 9 Therefore: length = 27 cm and width = 9 cm

First, calculate the length of the rectangle: L = 2x + 1 = 2*4 + 1 = 9. Next, determine the width: W = 3x - 5 = 3*4 - 5 = 7. Now, calculate the area: A = LW = 9 * 7 = 63 square centimeters (cm2).