There are actually several "standard forms" for line equations (point-slope form is one of them), so the exact details depend on which form you want.However, in general you can get rid of a fraction by multiplying all parts of the equation by the common denominator. For example, if somewhere in the equation you have a denominator of 5 (and no other denominators), you multiply everything by 5. That will get rid of the fraction.
Find the Least Common Multiple of all the denominators of the fractions in the equation. Then multiply each term by the LCM.
For example, if you have y/3 = 2*x + 1/2
The two fractions are 1/3 and 1/2. Their denominators, 3 and 2 have an LCM of 6.
Multiplying through by 6 gives: 2*y = 12*x + 3 [remember that even though it is not a fraction, 2*x also need to be multiplied].
Then rearrange to give the standard form: 12*x - 2*y - 3 = 0
For a vertical line, just write: x = ... (whatever the y-coordinate of any point on the line) To eliminate a fraction, you multiply both sides of the fraction by the denominator. If there are several fractions, you can multiply by the least common denominator (or by any common denominator, for that matter). For "standard form" ... Well, I believe there are several standard ways to write equations for straight lines.
ax2 + bx + c = 0
.983
The equation of the line is written in the standard form, y = mx+c
The quadratic equation, in its standard form is: ax2 + bx + c = 0 where a, b and c are constants and a is not zero.
For a vertical line, just write: x = ... (whatever the y-coordinate of any point on the line) To eliminate a fraction, you multiply both sides of the fraction by the denominator. If there are several fractions, you can multiply by the least common denominator (or by any common denominator, for that matter). For "standard form" ... Well, I believe there are several standard ways to write equations for straight lines.
You're talking about y=mx+b which is the standard line equation.
ax2 + bx + c = 0
.983
The equation of the line is written in the standard form, y = mx+c
The quadratic equation, in its standard form is: ax2 + bx + c = 0 where a, b and c are constants and a is not zero.
2X - y - 8 = 0the standard form of the equation is y = mx + chere you have to write the given equation in the standard form as in the form of y = mx + c2X - y - 8 = 0 - y -8 = -2x-y = -2x +8y = 2x -8so the standard form of the given equation is y = 2x - 8
It would have been helpful if you had actually given "this" equation. But since you have not bothered to share that crucial bit of information, I cannot provide a more useful answer.
Such an equation can be written in several standard forms; here are two of them: Ax + By + C = 0 y = mx + b (that's the "slope-intercept form")
Without an equality sign the given terms of an algebraic expression can't be classed as an equation and so therefore a solution is not possible.
it is 1
y + 4 = 2x −1