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If you mean circle equation: 100x^2 +100y^2 -120x +100y -39 = 0

Then divide all terms by 100: x^2 +y^2 -6/5x +y -39/100 = 0

Completing the squares: (x-3/5)^2 +(y+1/2)^2 = 1 which is radius squared

Center of circle: (3/5, -1/2)

Radius of circle: square root of 1 = 1 unit

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6y ago
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6y ago

Centre = (6, -1/2), radius = 10.

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Q: What is the center and radius of the circle 100x2 plus 100y2 -120x plus 100y -39 equals 0?
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