Assuming you mean a volume of 38 cm³ (as cm are a measure of length):
density = mass/volume = 277g / 38cm³ ≈ 7.289 g/cm³
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You need a third dimension (like the width of the refrigerator, or how far it goes back) in order to find the volume. Then you multiply all three dimensions together: volume = length * width * height. So this refrigerator would be 70.5 * 38 * ???
The size of spherical object with the weight of 38 pounds can be calculated if you know the density.The question states "stone".I prefer to perform such calculations in SI units (kilograms and meters) because it its SO much easier but just here I'll try using Avoirdupois and inches.The density of "stone" is not precise and as "geology.about.com" states:Rock density is very sensitive to the minerals that compose a particular rock type. Sedimentary rocks (and granite), which are rich in quartz and feldspar, tend to be less dense than volcanic rocks. And if you know your igneous petrology, you'll see that the more mafic a rock is, the greater its density.We will assume a density of 1,8 ounces per cubic inch (about 3 grams per cubic centimeter)38 pounds is 608 ounces608 / 1,8 is about 338 (that is the volume in cubic inches of the stone)V=4/3 pi r3 is the formula for the volume of a sphere338 = 4/3 * 3.1416 * r380.6 = r34,32 = rThe diameter of the 38 pound spherical stone is approximately 8,6 inchesDenser stone would give a smaller diameter, less dens stone a larger diameter.
V: total volume of tomato paste Vt : tomato in this volume First tomato paste is 38% then Vt=0.38 x V We want the tomato volume to be the same but the total volume to change so that to obtain 28% Vt = 0.28 x V' So we have 0.38 x V = 0.28 x V' thus V'/V = 0.38 / 0.28 = 19/14 = 1.357 So the volume of water to be added is about 35.7% of the total volume at the beginning
volume of soil needed = 38*5*1=190sq ft .12" = 1 feet
The "normal" PCV count for males is 48% and 38% for women. The count does not vary for changes in body mass.