d/dx of lnx is 1/x Therefore the derivative is 1/(1+x)
Derivative of x = 1, and since sqrt(x) = x^(1/2), derivative of x^(1/2) = (1/2)*(x^(-1/2))Add these two terms together and derivative = 1 + 1/(2*sqrt(x))
x= (x+1)/x(x+1)/x -x = 0f'(x) = ((x*1)-(x+1)) /x^2 -11/x^2 - 1
1 divided by x to the third power equals x to the negative third. The derivative of x to the negative third is minus three x to the negative fourth.
(-x+tanx)'=-1+(1/cos2x)
m
The derivative of x divided by 3 is 1/3. This can be found using the power rule of differentiation, where the derivative of x^n is nx^(n-1). In this case, x can be written as x^1, so the derivative is 1(1/3)*x^(1-1) = 1/3.
13
the derivative of ln x = x'/x; the derivative of 1 is 0 so the answer is 500(1/x)+0 = 500/x
d/dx of lnx is 1/x Therefore the derivative is 1/(1+x)
(1/2(x^-1/2))/x
x= (x+1)/x(x+1)/x -x = 0f'(x) = ((x*1)-(x+1)) /x^2 -11/x^2 - 1
Derivative of x = 1, and since sqrt(x) = x^(1/2), derivative of x^(1/2) = (1/2)*(x^(-1/2))Add these two terms together and derivative = 1 + 1/(2*sqrt(x))
1 divided by x to the third power equals x to the negative third. The derivative of x to the negative third is minus three x to the negative fourth.
(-x+tanx)'=-1+(1/cos2x)
Following the correct order of operations: derivative of x^2 + 6/2 = derivative of x^2 +3, which equals 2x
(cos x sin x) / (cos x sin x) = 1. The derivative of a constant, such as 1, is zero.