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Given y = tan x:
dy/dx = sec^2 x(secant of x squared)
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What is the derivative of 40xy where x equals 2 and y equals 2?
- the derivative with respect to x is 40y - The derivative with respect to Y is 40xSo, since both x and y equal 2, both derivatives yield 40*2 = 80
What is the derivative of y equals xln x?
(xlnx)' = lnx + 1
Determine the x coordinate of the point where the derivative of y equals x square - 2x equals 0?
x=2
How do you derivative x plus y - 1 equals ln x2 plus y2?
There are several steps involved in how one can solve the derivative x plus y - 1 equals x2 plus y2. The final answer to this math problem is y'(x) = (1-2 x)/(2 y-1).
What is the derivative of y equals aex plus be2x plus ce3x with respect to x?
if y=aex+be2x+ce3x then its derivative dy/dx or y' is: y'=aex+2be2x+3ce3x
What is the derivative of y equals sec x?
sec(x)tan(x)
What is the derivative of 40xy where x equals 2 and y equals 2?
- the derivative with respect to x is 40y - The derivative with respect to Y is 40xSo, since both x and y equal 2, both derivatives yield 40*2 = 80
What is the derivative of y equals 36cotx?
Y = 36cot(x)Y' = dy/dx36cot(x)= - 36csc2(x)==========
How do you find the mean of x over y equals a over b?
Find the derivative of Y and then divide that by the derivative of A
Find the derivative of y equals 3cosx?
y=3 cos(x) y' = -3 sin(x)
What is the derivative of y equals xln x?
(xlnx)' = lnx + 1
Determine the x coordinate of the point where the derivative of y equals x square - 2x equals 0?
x=2
Why was the calculus student confused about y equals ex and the derivative of y equals ex?
Because the derivative of e^x is e^x (the original function back again). This is the only function that has this behavior.
What is the rate of change in the function y equals tan3x?
In this case, you'll need to apply the chain rule, first taking the derivative of the tan function, and multiplying by the derivative of 3x: y = tan(3x) ∴ dy/dx = 3sec2(3x)
How do you derivative x plus y - 1 equals ln x2 plus y2?
There are several steps involved in how one can solve the derivative x plus y - 1 equals x2 plus y2. The final answer to this math problem is y'(x) = (1-2 x)/(2 y-1).
What is the derivative of y equals sin times x to the power of 2?
D(y)= sin 2x
If sin b equals to x over y where b is acute find tan b in terms of x?
tan(b) = x/sqrt(y^2-x^2)
