y"+y'=0 is a differential equation and mean the first derivative plus the second derivative =0.Look at e-x the first derivative is -e-xThe second derivative will be e-xThe sum will be 0
D(y)= sin 2x
sec(x)tan(x)
If dy/dx = (e) (9x) then Y = 4.5ex2 plus (any constant).==================================The above answer explains how to get the integral of e9x.If you were interested in how to get the derivative of e9x, the answer is e9.I suspect you may have actually wanted to ask how to get the derivative of e9x.In that case, the derivative of e9x is 9e9x.
y = -5
Find the derivative of Y and then divide that by the derivative of A
y is a sum of constants and so is itself a constant. Its derivative is, therefore, zero.
Derivative of sin x = cos x, so chain rule to derive 8x = 8 , answer is 8cos8x
- the derivative with respect to x is 40y - The derivative with respect to Y is 40xSo, since both x and y equal 2, both derivatives yield 40*2 = 80
y"+y'=0 is a differential equation and mean the first derivative plus the second derivative =0.Look at e-x the first derivative is -e-xThe second derivative will be e-xThe sum will be 0
(xlnx)' = lnx + 1
if y=aex+be2x+ce3x then its derivative dy/dx or y' is: y'=aex+2be2x+3ce3x
y=(2x)2 y=2(2x) y=4x
Because the derivative of e^x is e^x (the original function back again). This is the only function that has this behavior.
Y = 36cot(x)Y' = dy/dx36cot(x)= - 36csc2(x)==========
D(y)= sin 2x
sec(x)tan(x)