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Eighty years (there was no 'year zero' !).

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7y ago

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It is 79 years - remember, there was no year 0.

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7y ago
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Q: What is the distance between 40 BC and 40 AD?
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How many years are there between 30 BC and 30 AD and why?

58 years are between 30 BC and AD 30. The first thing you need to remember is that there is no year 0; the year before AD 1 is 1 BC. So the years between 30 BC and AD 30 are... 29 BC, 28 BC, 27 BC, ..., 2 BC, 1 BC, AD1, AD 2, ..., AD 27, AD 28, AD 29 29 BC through 1 BC is 29 years, and AD 1 through AD 29 is 29 years. 29 years + 29 years = 58 years


How many years between 10 BC and 10 AD?

There are 19 years between 10 BC and 10 AD. The reason for this is that there is no year 0 in the Gregorian calendar system, so the year following 1 BC is 1 AD. Therefore, you need to count from 10 BC to 1 AD (10 years) and then add the 9 years from 1 AD to 10 AD, totaling 19 years.


How many years was 27 bc to 69 ad?

The years between 27BC and 69 AD is 96 Years.


Can you always find another fraction in between ant two fractions why?

Yes. The simple answer is that rational fractions are infinitely dense. A longer proof follows:Suppose you have two fractions a/b and c/d where a, b, c and d are integers and b, d are positive integers.Without loss of generality, assume a/b < c/d.The inequality implies that ad < bc so that bc-ad>0 . . . . . . . . . . . . . . . . . . . (I)Consider (ad + bc)/(2bd)Then (ad+bc)/2bd - a/b = (ad+bc)/2bd - 2ad/2bd = (bc-ad)/2bdBy definition, b and d are positive so bd is positive and by result (I), the numerator is positive.That is to say, (ad+bc)/2bd - a/b > 0 or (ad+bc)/2bd > a/b.Similarly, by considering c/d - (ad+bc)/2bd is can be shown that c/d > (ad+bc)/2bd.Combining these results,a/b < (ad+bc)/2bd < c/d.


What is the difference between 739 BC and AD 465?

739 BC happened 739 years before the birth of Christ, and 465 AD happened 465 years after his death.