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mate, we would have two different points from the x intercept and the y intercept.

The first point would be (5,0), the second would be (0,-4), which we find from the intercepts.

thus now we can use the equation.

y-y1=y2-y1

x-x1 x2-x1 where you can substitute these two points into the equation

Hence:

y-0=-4

x-5 -5

which then equals,

-5y=-4(x-5) which we expand

-5y= -4x+20, now we move the -4x+20 to the otherside of the equation, effectively multiplying it by -1

thus, 4x-5y-20=0, and that is your equation for your question.

Greetings from Australia

Q: What is the equation for the line whose x-intercept is 5 and whose y-intercept is -4?

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A linear equation.

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