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mate, we would have two different points from the x intercept and the y intercept.
The first point would be (5,0), the second would be (0,-4), which we find from the intercepts.
thus now we can use the equation.
y-y1=y2-y1
x-x1 x2-x1 where you can substitute these two points into the equation
Hence:
y-0=-4
x-5 -5
which then equals,
-5y=-4(x-5) which we expand
-5y= -4x+20, now we move the -4x+20 to the otherside of the equation, effectively multiplying it by -1
thus, 4x-5y-20=0, and that is your equation for your question.
Greetings from Australia
A linear equation.
It is the locus of all points whose coordinates satisfy the equation of the line.
A linear equation.
When a straight line equation is parallel to another equation the slope remains the same but the y intercept changes
y=mx+c
Without the inclusion of an equality sign and not knowing the plus or minus values of the given terms it can't be considered to be a straight line equation
You can write it either in standard form (ax + by = c) or in slope-intercept form (y = mx + b)
A linear equation.
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That would be a linear equation.
yes
2y= 3x+6
It is the locus of all points whose coordinates satisfy the equation of the line.
A linear equation.
When a straight line equation is parallel to another equation the slope remains the same but the y intercept changes
y=mx+c
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