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What is the equation of the line from the origin to the midpoint of the points 3 2 and 5 -1 on the Cartesian plane?
Wiki User
∙ 7y ago
Points: (3, 2) and (5, -1)
Midpoint: (4, 0.5)
End points of line: (0, 0) and (4, 0.5)
Slope of line: 1/8
Equation of line: y-0.5 = 1/8(x-4) => y = 1/8x
Wiki User
∙ 7y ago
Wiki User
∙ 7y agoIt is x - 4y = 0
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What is the Cartesian equation of a circle whose end points of its diameter are at 10 -4 and 2 2?
End points: (10, -4) and (2, 2) Midpoint: (6, -1) which is the centre of the circle Distance from (6, -1) to any of its end points = 5 which is the radius Therefore the Cartesian equation is: (x-6)^2 +(y+1)^2 = 25
What is the equation of a circle whose diameter end points are at 8 7 and 2 -3 on the Cartesian plane?
End points: (8, 7) and (2, -3) Midpoint: (5, 2) which is the center of the circle Radius: square root of 34 Equation of the circle: (x-5)^2 +(y-2)^2 = 34
What is the midpoint of -12 and 73?
The midpoint between -12 and 73 is 30.5. To find the midpoint, add the two numbers together and divide by 2. (-12 + 73) ÷ 2 = 30.5.
What is the equation and its perpendicular bisector equation of the line whose end points are at -2 3 and 1 -1 on the Cartesian plane?
Points: (-2, 3) and (1, -1) Midpoint: (-0.5, 1) Slope: -4/3 Perpendicular slope: 4/3 Equation: 3y = -4x+1 Perpendicular bisector equation: 4y = 3x+5.5
What is the perpendicular bisector equation of the line whose end points are at s 2s and 3s 8s on the Cartesian plane?
Points: (s, 2s) and (3s, 8s) Midpoint: (2s, 5s) Slope: 3 Perpendicular slope: -1/3 Perpendicular equation: y -5s = -1/3(x -2s) => 3y = -x +17s Perpendicular bisector equation in its general form: x +3y -17s = 0
What is the equation and its distance from origin that meets the line joining the points 13 17 and 19 23 at its midpoint on the Cartesian plane showing work?
Points: (13, 17) and (19, 23) Midpoint: (16, 20) Slope of required equation: 5/4 Its equation: 4y = 5x or as y = 1.25x Its distance from (0, 0) to (16, 20) = 4 times sq rt 41
What is the equation that meets the coordinates of 3 2 and 5 -1 at their midpoint and stems from the origin?
The equation from the origin to the midpoint of the given points works out as y = 1/8x whereas 1/8 is the slope and there is no y intercept.
What is the Cartesian equation of a circle whose end points of its diameter are at 10 -4 and 2 2?
End points: (10, -4) and (2, 2) Midpoint: (6, -1) which is the centre of the circle Distance from (6, -1) to any of its end points = 5 which is the radius Therefore the Cartesian equation is: (x-6)^2 +(y+1)^2 = 25
What is the midpoint equation?
Midpoint equation also called midpoint formula is the formula to identify the middle point of the two end points. The formula for midpoint is ( {X2 + X1}/2 , {Y2 + Y1}/2 ).
What is the perpendicular bisector equation of the line with end points of -1 4 and 3 8 on the Cartesian plane?
Points: (-1, 4) and (3, 8) Midpoint (1, 6) Slope: 1 Perpendicular slope: -1 Perpendicular bisector equation: y-6 = -1(x-1) => y = -x+7
What is the equation of a circle whose diameter end points are at 8 7 and 2 -3 on the Cartesian plane?
End points: (8, 7) and (2, -3) Midpoint: (5, 2) which is the center of the circle Radius: square root of 34 Equation of the circle: (x-5)^2 +(y-2)^2 = 34
What is the perpendicular bisector equation that meets the line 13 19 and 23 17 at midpoint on the Cartesian plane showing all aspects of work with answer?
Points: (13, 19) and (23, 17) Midpoint: (18, 18) Slope: -1/5 Perpendicular slope: 5 Perpendicular equation: y-18 = 5(x-18) => y = 5x-72
What is the midpoint of -12 and 73?
The midpoint between -12 and 73 is 30.5. To find the midpoint, add the two numbers together and divide by 2. (-12 + 73) ÷ 2 = 30.5.
What is the equation of the line whose end points are 5 2 and 3 2 on the Cartesian plane?
The equation is y = 2
What is the equation and its perpendicular bisector equation of the line whose end points are at -2 3 and 1 -1 on the Cartesian plane?
Points: (-2, 3) and (1, -1) Midpoint: (-0.5, 1) Slope: -4/3 Perpendicular slope: 4/3 Equation: 3y = -4x+1 Perpendicular bisector equation: 4y = 3x+5.5
What is the perpendicular bisector equation of the line segment whose end points are at -2 4 and -4 8 on the Cartesian plane?
End points: (-2, 4) and (-4, 8) Midpoint: (-3, 6) Slope: -2 Perpendicular slope: 1/2 Perpendicular bisector equation: y -6 = 1/2(x--3) => y = 0.5x+7.5
What is the perpendicular bisector equation of the line joined by the points -2 5 and -8 -3 on the Cartesian plane?
Points: (-2, 5) and (-8, -3) Midpoint: (-5, 1) Slope: 4/3 Perpendicular slope: -3/4 Perpendicular equation: y-1 = -3/4(x--5) => 4y = -3x-11 Perpendicular bisector equation in its general form: 3x+4y+11 = 0
