0
Midpoint equation also called midpoint formula is the formula to identify the middle point of the two end points. The formula for midpoint is ( {X2 + X1}/2 , {Y2 + Y1}/2 ).
What else can I help you with?
What is the midpoint between 6 -2 and -4 4?
(1,1). The midpoint between 6 & -4 is 1, and the midpoint between -2 and 4 is 1. The equation for this line is y = -0.6*x + 1.6, by the way. Check that (1,1) lies on the line.
What is the perpendicular equation that meets the line of 2 3 and 5 7 at its midpoint showing key aspects of work?
Here are the key steps:* Find the midpoint of the given line. * Find the slope of the given line. * Divide -1 (minus one) by this slope, to get the slope of the perpendicular line. * Write an equation for a line that goes through the given point, and that has the given slope.
How do you find the right bisector of a triangle?
For triangle ABC, find the midpoint of side BC. Then, find the slope of side BC and use its negative reciprocal (since the negative reciprocal slope is the slope of the right bisector joining side BC and the opposite vertex). Finally, substitute the midpoint and negative reciprocal slope into the y=mx+b equation to get "b", then write the equation. :)
What is the midpoint of 3x equals 5x-6?
First of all 3x=5x-6 is the same as 2x=6 or x=3 The graph of this equation is a vertical line and in order to have a midpoint, you need some endpoints. Otherwise, the line goes up and down infinitely in both directions
What is the equation of the straight line extending from the origin to the midpoint of the line joining 3 2 and 5 -1?
1st find the midpoint -- (4, 1/2) Now slope -- 1/2 divided by 4 = 1/8 y-intercept = 0 (origin) y = (1/8)x <--- answer
What is the equation that meets the coordinates of 3 2 and 5 -1 at their midpoint and stems from the origin?
The equation from the origin to the midpoint of the given points works out as y = 1/8x whereas 1/8 is the slope and there is no y intercept.
What is the midpoint between 6 -2 and -4 4?
(1,1). The midpoint between 6 & -4 is 1, and the midpoint between -2 and 4 is 1. The equation for this line is y = -0.6*x + 1.6, by the way. Check that (1,1) lies on the line.
What is in its general form the perpendicular bisector equation meeting the line segment of s 2s and 3s 8s at its midpoint?
Points: (s, 2s) and (3s, 8s) Slope: 3 Perpendicular slope: -1/3 Midpoint: (2s, 5s) Equation in its general form: x+3y-17 = 0
What is the equation and its distance from origin that meets the line joining the points 13 17 and 19 23 at its midpoint on the Cartesian plane showing work?
Points: (13, 17) and (19, 23) Midpoint: (16, 20) Slope of required equation: 5/4 Its equation: 4y = 5x or as y = 1.25x Its distance from (0, 0) to (16, 20) = 4 times sq rt 41
What is the equation of the straight line from the origin to the midpoint of the line joining 3 2 and 5 -1?
It will have no y intercept and it is: y = 0.125x
What is the perpendicular bisector equation that meets the line segment of -2 2 and 6 4 at its midpoint showing work?
Points: (-2, 2) and (6, 4) Midpoint: (2, 3) Slope: 1/4 Perpendicular slope: -4 Perpendicular bisector equation: y-3 = -4(x-2) => y = -4x+11
How do you find the midpoint when doing math?
Hi You take two graph points x,y and x1,y1 Use the midpoint equation : (x1+x)/2 = midpoint x , and (y1+y)/2 = midpoint y For a example (1,3) and ( 4,5) What the midpoint of it? Midpoint x = (4+1)/2 = 5/2 = 2 1/2 Midpoint y = (5+3)/2 = 8/2 = 4 So the midpoint of points (1,3) and (4,5) is ( 2 1/2 , 4 ) Just graph it and will see for yourself it works.
What is the perpendicular bisector equation that meets the line 13 19 and 23 17 at midpoint on the Cartesian plane showing all aspects of work with answer?
Points: (13, 19) and (23, 17) Midpoint: (18, 18) Slope: -1/5 Perpendicular slope: 5 Perpendicular equation: y-18 = 5(x-18) => y = 5x-72
What is the perpendicular equation that meets the line of 7 3 and -6 1 at its midpoint showing work?
Points: (7, 3) and (-6, 1) Midpoint: (0.5, 2) Slope: 2/13 Perpendicular slope: -13/2 Perpendicular equation: y-2 = -13/2(x-0.5) => 2y-4 = -13x+6.5 => 2y = -13x+10.5
What is the perpendicular equation that meets the line of 2 3 and 5 7 at its midpoint showing key aspects of work?
Here are the key steps:* Find the midpoint of the given line. * Find the slope of the given line. * Divide -1 (minus one) by this slope, to get the slope of the perpendicular line. * Write an equation for a line that goes through the given point, and that has the given slope.
What is the equation to find the midpoint?
The mid-point of the line segment of (x1, y1) and (x2, y2) is (x1+X2)/2 and (y1+y2)/2
How do you find the right bisector of a triangle?
For triangle ABC, find the midpoint of side BC. Then, find the slope of side BC and use its negative reciprocal (since the negative reciprocal slope is the slope of the right bisector joining side BC and the opposite vertex). Finally, substitute the midpoint and negative reciprocal slope into the y=mx+b equation to get "b", then write the equation. :)
