Midpoint equation also called midpoint formula is the formula to identify the middle point of the two end points. The formula for midpoint is ( {X2 + X1}/2 , {Y2 + Y1}/2 ).
(1,1). The midpoint between 6 & -4 is 1, and the midpoint between -2 and 4 is 1. The equation for this line is y = -0.6*x + 1.6, by the way. Check that (1,1) lies on the line.
Here are the key steps:* Find the midpoint of the given line. * Find the slope of the given line. * Divide -1 (minus one) by this slope, to get the slope of the perpendicular line. * Write an equation for a line that goes through the given point, and that has the given slope.
For triangle ABC, find the midpoint of side BC. Then, find the slope of side BC and use its negative reciprocal (since the negative reciprocal slope is the slope of the right bisector joining side BC and the opposite vertex). Finally, substitute the midpoint and negative reciprocal slope into the y=mx+b equation to get "b", then write the equation. :)
First of all 3x=5x-6 is the same as 2x=6 or x=3 The graph of this equation is a vertical line and in order to have a midpoint, you need some endpoints. Otherwise, the line goes up and down infinitely in both directions
the midpoint of 0.09 and 0.1
The equation from the origin to the midpoint of the given points works out as y = 1/8x whereas 1/8 is the slope and there is no y intercept.
(1,1). The midpoint between 6 & -4 is 1, and the midpoint between -2 and 4 is 1. The equation for this line is y = -0.6*x + 1.6, by the way. Check that (1,1) lies on the line.
Points: (s, 2s) and (3s, 8s) Slope: 3 Perpendicular slope: -1/3 Midpoint: (2s, 5s) Equation in its general form: x+3y-17 = 0
Points: (13, 17) and (19, 23) Midpoint: (16, 20) Slope of required equation: 5/4 Its equation: 4y = 5x or as y = 1.25x Its distance from (0, 0) to (16, 20) = 4 times sq rt 41
It will have no y intercept and it is: y = 0.125x
Points: (-2, 2) and (6, 4) Midpoint: (2, 3) Slope: 1/4 Perpendicular slope: -4 Perpendicular bisector equation: y-3 = -4(x-2) => y = -4x+11
Hi You take two graph points x,y and x1,y1 Use the midpoint equation : (x1+x)/2 = midpoint x , and (y1+y)/2 = midpoint y For a example (1,3) and ( 4,5) What the midpoint of it? Midpoint x = (4+1)/2 = 5/2 = 2 1/2 Midpoint y = (5+3)/2 = 8/2 = 4 So the midpoint of points (1,3) and (4,5) is ( 2 1/2 , 4 ) Just graph it and will see for yourself it works.
Points: (13, 19) and (23, 17) Midpoint: (18, 18) Slope: -1/5 Perpendicular slope: 5 Perpendicular equation: y-18 = 5(x-18) => y = 5x-72
Points: (7, 3) and (-6, 1) Midpoint: (0.5, 2) Slope: 2/13 Perpendicular slope: -13/2 Perpendicular equation: y-2 = -13/2(x-0.5) => 2y-4 = -13x+6.5 => 2y = -13x+10.5
Here are the key steps:* Find the midpoint of the given line. * Find the slope of the given line. * Divide -1 (minus one) by this slope, to get the slope of the perpendicular line. * Write an equation for a line that goes through the given point, and that has the given slope.
midpoint postulate
The mid-point of the line segment of (x1, y1) and (x2, y2) is (x1+X2)/2 and (y1+y2)/2