3x + 3 (y-z)
Dont trip B****
3(x+y-z)
5x-2y+3z-2x-y-4z=3x-3y-z
3x-3y+7z
6
Ex. 5x-2y+3z-2x-y+4z Alright so this is how i do it: I circle all the ones that have the x as variables and are like terms. (you don't have to do this, but i find it helps and makes it go faster) So i would have circled 5x and -2x because the sign in front of the term is with the term. Then i would have added together the two terms and that would end up being 3x because 5x plus -2x is 3x. and i write 3x down below. then i would have gone to the next thing in the problem which would be the y's. -2y and -y. when added together it is -3y. so i write -3y below with 3x so it should be 3x-3y. Then i go to the z's. 3z and 4z. 3z+4z is 7z. so i write that below. so far it should be: 3x-3y+7z because 7z is positive. And that is your final answer because you can't simplify any more because they are not like terms.
6x - 2y + 3xz - yz = (z + 2)(3x - y) 9x - 3y = 3(3x - y) (3x - y) over (3x - y) equals 1, so they can be canceled out. The simplified expression is (z + 2) over 3.
4.34684352143
3y+2z
Rearrange the equations in the form of: x+3y = 17z 3*(3x-y = z) Multply the second equation by 3: x+3y = 17z 9x-3y = 3z Add them together to eliminate y: 10x = 20z Divide both sides by 10: x = 2z Substitute the value of x into the original equations to find the value of y: Therefore the point of intersection is: (2z, 5z)
Solve this system of equations. 5x+3y+z=-29 x-3y+2z=23 14x-2y+3z=-18 Write the solution as an ordered triple.