What is the factor of x2-3?

Answer 1

That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: (1 plus or minus the square root of 253) divided by 2

x = 8.452986860293432

x = -7.452986860293433

Answer 2

Find two numbers whose sum is -2 and whose product is -3.

Equivalently, find two positive numbers such that their difference is 2 and their product is 3.

The numbers are 1 and 3.

Since the middle term is negative, the larger of these numbers is negative in its factor.

The factorisation is (x - 3)*(x + 1)

Answer 3

To find the factors of the quadratic expression x^2 - 3, we need to factorize it by looking for two numbers that multiply to -3 and add up to the coefficient of the linear term, which is 0 in this case. The factors are (x + √3)(x - √3) or (x + √3)(x - √3). This is because when you expand these factors using the distributive property, you get x^2 - 3.

Answer 4

Oh, dude, you're hitting me with some math lingo now. So, the factor of x^2-3 is actually (x+√3)(x-√3). It's like when you break up with someone - you gotta find the right combination to make it work, you know what I mean?

Answer 5

(x + the square root of 3)(x - the square root of 3)

Answer 6

The expression does not have rational factors.

Answer 7

(x + 1)(x - 3)

Answer 8

(x - 1)(x2 + x + 1)

Answer 9

Factor x2-3 is: (x+sqrt3)(x-sqrt3).