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There are an infinity of lines passing through the point whose coordinates are (2,2), each with a different slope [gradient]. The equation of the line will be of the form (y - 2) = m*(x - 2) where m is the gradient.
A linear equation.
Rearranging the original equation, we get y=-(2/3)x+12. Since 12 is the constant, this is the point that the line of this equation will cut the y-axis if x=0. Therefore, -(2/3) is the gradient and for an equation to produce a parallel line, the gradient must be equal. Summing up, y=-(2/3)+c (where c equals any real number) would be parallel
The equation of a line can be expressed in the slope-intercept form, which is ( y = mx + b ), where ( m ) is the gradient and ( b ) is the y-intercept. Given a gradient of -3 and that the line passes through the origin (0,0), the y-intercept ( b ) is 0. Thus, the equation of the line is ( y = -3x ).
Change the number in front of the X, as that is the gradient.
There are an infinity of lines passing through the point whose coordinates are (2,2), each with a different slope [gradient]. The equation of the line will be of the form (y - 2) = m*(x - 2) where m is the gradient.
A linear equation.
Rearranging the original equation, we get y=-(2/3)x+12. Since 12 is the constant, this is the point that the line of this equation will cut the y-axis if x=0. Therefore, -(2/3) is the gradient and for an equation to produce a parallel line, the gradient must be equal. Summing up, y=-(2/3)+c (where c equals any real number) would be parallel
An equation such as y = mx + c is said to be in standard form. From such an equation, Gradient = coefficient of x = 3
That would be a linear equation.
yes
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If you have the equation, yes. If the equation is given in terms of x and y, make y the subject of the equation. That is, expres the equation in the form y = mx + c where m and c are constants. Then the gradient is m.
If necessary, rearrange the linear equation so that it is in the slope-intercept form: y = mx + c Then the gradient of the line is m.
2y= 3x+6
Change the number in front of the X, as that is the gradient.
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