-2
6000.
The number is 23.
3201
the sum of my digits is 6? answer=60
Smallest 6 digit no. is 100,000. Largest 5 digits number is 99,999 There sum is 199,999
Add the digits together. The sum of the digits of 23 is 5.
ten ones with an infinite number of zeroes.
The number is 23.
-9
256
3201
47 + 74 = 121
41
the sum of my digits is 6? answer=60
Add the digits together. The sum of the digits of 23 is 5.
The number is 45. The sum of its digits i.e. 4+5=9 Five times the sum of its digits i.e. 5 times 9 which is 45
Nine hundred thirty (930) is the highest three digit number whose digits have a sum of 12. 9+3+0=12. Any numbers higher than that will give you an sum greater than 12.
(9,999) + (9,999) = 19,998 So it looks like the sum of two 4-digit numbers can't have more than 5 digits.