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# What is the height of a parallelogram if the area is 54 and the base is 9?

Updated: 10/31/2022

Wiki User

13y ago

it is 12 for sure good luck

cierra harris

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3y ago

Wiki User

13y ago

6

Anonymous

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4y ago

ion know

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Q: What is the height of a parallelogram if the area is 54 and the base is 9?
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### What is the area of a parallelogram if the base is 6 meters and the height is 9 meters?

Area = 6*9 = 54 square meters

### What is the area of 9cm base and 6cm height?

It would help to answer the question if there was any information about the shape itself: a triangle, a parallelogram, ... Clearly, that was too much to expect.

### What is the area of a triangle in square meters if it has a base of 54 centimeters and a height of 1.2 meters?

32.4 cm2 - The formula for calcuating the area of a triangle is:- (base/2) x height

### What is the volume of a triangle prism when the area of the base is 54m squared and the height is 23 m?

Volume of prism = Base area x height = 54 square metres x 23 metres = 1242 cubic metres.

### What is the area of a triangle if the base is 9 inches and height is 12 inches?

Area = 1/2*9*12 = 54 square inches

### What is the area of a parallelogram with a circle inside the base of the parallelogram is 9 and the diameter of the circle is 6?

Since the area of the circle would be multiplied due to the circumference of the pathogenic therum,so you would multiply 54x2=108.Then multiply that by 54,which is the absolute value of the area of the parallelogram,so 54x108,is 5832,which you'd find the square root of,76.4. :)

### What is the area of a triangle with base 12 cm and height 9 cm?

12x9=108 108/2=54 54cm

### What is the area of a trazepoid with a height of 4m and base of 15m and 12 m?

0.5*(15+12)*4 = 54 sq m

### How do you get the base of a triangle when the area is 54 and the height is two more than twice the base?

The area of a triangle is 1/2 base times height. The height in this case is 2b+2. So the equation is54 = 1/2b(2b+2)54=(1/2)(2b^2+2b)54=b^2+bb^2+b-54when you use the quadratic formula you get about6.86545993and-7.86545993and since a side can't be negative it has to be the first answer. Then we double check by plugging 6.865 into 1/2b(2b+2) so1/2(6.865)(2*6.865+2)3.4325(13.73+2) = 3.4325(15.73)and you get approxmiately 54.Your final answer to the question "how long is the base" is, "the base of the triangle is 6.865 (unless you want to write out the whole equation).If the question was "how do you find the base of a triangle with an area of 54 and the height is two more than twice the base" then you would answer, "The height can be represented as (2b+2) where b is the base. Then, since h=2b+2, you can substitute (2b+2) in for h in the triangle area formula (A=1/2bh), set A equal to 54 (which is a given), and then solve for b."Hope this helped =).

### What is the area and perimeter of a base of 15 and a height of 12?

If it's a rectangle then:- Area = 15*12 = 180 square units Perimeter = 15+15+12+12 = 54 units of measurement

### Adjacent sides of a parallelogram differ in length by 3 cm. The perimeter is 60 cm and the area is 45 cm2. What is the measure of an acute angle of the parallelogram?

Let the length of the shorter sides be x cm long; then the longer sides are x + 3 cm long Using the perimeter x can be found: perimeter = x + x+3 + x + x+3 = 4x + 6 = 60 &rarr; 4x = 54 x = 13.5 cm Longer side = x + 3 = 13.5 + 3 = 16.5 Using one of the longer sides as the base of the parallelogram the height (perpendicular distance between the base and its parallel side) of the parallelogram can be found from the area: area = base &times; height &rarr; 45 cm&sup2; = 16.5 cm &times; height &rarr; height = 45/16.5 cm = 2 8/11 cm Using trigonometry, the sine of the angle is the height over the shorter side which forms the hypotenuse of a right angle triangle: sin &theta; = (2 8/11) / 13.5 = 20/99 &rarr; &theta; = arcsin(20/99) &asymp; 11.66&deg; You could use the shorter side as the base in which case the longer side is the hypotenuse and: height = 45/13.5 cm = 3 1/3 cm sin &theta; = (3 1/3) / 16.5 = 20/99 &rarr; &theta; = arcsin(20/99) &asymp; 11.66&deg;