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it is 12 for sure good luck

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Q: What is the height of a parallelogram if the area is 54 and the base is 9?

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54

Area = 6*9 = 54 square meters

0.5*(15+12)*4 = 54 sq m

Let the length of the shorter sides be x cm long; then the longer sides are x + 3 cm long Using the perimeter x can be found: perimeter = x + x+3 + x + x+3 = 4x + 6 = 60 → 4x = 54 x = 13.5 cm Longer side = x + 3 = 13.5 + 3 = 16.5 Using one of the longer sides as the base of the parallelogram the height (perpendicular distance between the base and its parallel side) of the parallelogram can be found from the area: area = base × height → 45 cm² = 16.5 cm × height → height = 45/16.5 cm = 2 8/11 cm Using trigonometry, the sine of the angle is the height over the shorter side which forms the hypotenuse of a right angle triangle: sin θ = (2 8/11) / 13.5 = 20/99 → θ = arcsin(20/99) ≈ 11.66° You could use the shorter side as the base in which case the longer side is the hypotenuse and: height = 45/13.5 cm = 3 1/3 cm sin θ = (3 1/3) / 16.5 = 20/99 → θ = arcsin(20/99) ≈ 11.66°

The formula for the area of a rectangle is *length×width* , so the answer would be 54 cm squared.

Related questions

54

Area = 6*9 = 54 square meters

It would help to answer the question if there was any information about the shape itself: a triangle, a parallelogram, ... Clearly, that was too much to expect.

32.4 cm2 - The formula for calcuating the area of a triangle is:- (base/2) x height

Volume of prism = Base area x height = 54 square metres x 23 metres = 1242 cubic metres.

Area = 1/2*9*12 = 54 square inches

Since the area of the circle would be multiplied due to the circumference of the pathogenic therum,so you would multiply 54x2=108.Then multiply that by 54,which is the absolute value of the area of the parallelogram,so 54x108,is 5832,which you'd find the square root of,76.4. :)

12x9=108 108/2=54 54cm

0.5*(15+12)*4 = 54 sq m

The area of a triangle is 1/2 base times height. The height in this case is 2b+2. So the equation is54 = 1/2b(2b+2)54=(1/2)(2b^2+2b)54=b^2+bb^2+b-54when you use the quadratic formula you get about6.86545993and-7.86545993and since a side can't be negative it has to be the first answer. Then we double check by plugging 6.865 into 1/2b(2b+2) so1/2(6.865)(2*6.865+2)3.4325(13.73+2) = 3.4325(15.73)and you get approxmiately 54.Your final answer to the question "how long is the base" is, "the base of the triangle is 6.865 (unless you want to write out the whole equation).If the question was "how do you find the base of a triangle with an area of 54 and the height is two more than twice the base" then you would answer, "The height can be represented as (2b+2) where b is the base. Then, since h=2b+2, you can substitute (2b+2) in for h in the triangle area formula (A=1/2bh), set A equal to 54 (which is a given), and then solve for b."Hope this helped =).

If it's a rectangle then:- Area = 15*12 = 180 square units Perimeter = 15+15+12+12 = 54 units of measurement

Let the length of the shorter sides be x cm long; then the longer sides are x + 3 cm long Using the perimeter x can be found: perimeter = x + x+3 + x + x+3 = 4x + 6 = 60 → 4x = 54 x = 13.5 cm Longer side = x + 3 = 13.5 + 3 = 16.5 Using one of the longer sides as the base of the parallelogram the height (perpendicular distance between the base and its parallel side) of the parallelogram can be found from the area: area = base × height → 45 cm² = 16.5 cm × height → height = 45/16.5 cm = 2 8/11 cm Using trigonometry, the sine of the angle is the height over the shorter side which forms the hypotenuse of a right angle triangle: sin θ = (2 8/11) / 13.5 = 20/99 → θ = arcsin(20/99) ≈ 11.66° You could use the shorter side as the base in which case the longer side is the hypotenuse and: height = 45/13.5 cm = 3 1/3 cm sin θ = (3 1/3) / 16.5 = 20/99 → θ = arcsin(20/99) ≈ 11.66°