using normal algebraic methods, all I can get is m=0 and y=all numbers
M=3 because y+y+y= 3xY and MY= MxY
-1
y=m(x)+b
If y = mx + b, then x = (y-b)/m (for m not equal to zero).
using normal algebraic methods, all I can get is m=0 and y=all numbers
M=3 because y+y+y= 3xY and MY= MxY
-1
y-b/x=m
y=m(x)+b
m = xn/(n + y)
the answer is: (y-b)/x = m y = mx + b y - b = mx (y-b)/x = m
m = slope of the line. b = the Y intercept.
well, m is the slope and c is the y-intercept
Y = mX + 6 Y - 6 = mX (Y - 6)/X = m ==============If you had values you could get the integer that is m
y = mx + b
If y = mx + b, then x = (y-b)/m (for m not equal to zero).