28
a cordinate
Point (0, 1) is a single point and it would be in the coordinate (not cordinate) plane. And I have no idea what "you" is doing at the end of the question!
0
The midpoint is (0, 1)
The midpoint of a class interval can be found by averaging the lower and upper boundaries. For the class interval 1-17, the midpoint is calculated as (1 + 17) / 2, which equals 9. Therefore, the midpoint of the class 1-17 is 9.
If you mean endpoints of (0, 0) and (0, -12) then the midpoint is (0, -6)
a cordinate
Point (0, 1) is a single point and it would be in the coordinate (not cordinate) plane. And I have no idea what "you" is doing at the end of the question!
Midpoint: (1, 1)
0
The number at the midpoint of these two numbers is (15 + 27)/2 = 21
The midpoint is (0, 1)
If you mean points of (-1, 10) and (9, -1) then the midpoint is (4, 4.5)
Diameter endpoints: (2, 7) and (-6, -1) Centre of circle will be the midpoint which is: (-2, 3)
Endpoints: (1, -6) and (-3, 4) Midpoint: (-1, -1)
The midpoint of the hypotenuse equidistant from all the vertices
Endpoints: (1, -6) and (-3, 4) Midpoint: (-1, -1)