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Q: What is the midpoint of the line segment with endpoints (1-6) (-34)?

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If you mean endpoints of (16, 5) and (-6, -9) then its midpoint is (5, -2)

Endpoints: (-1, 3) and (-2, -5) Midpoint: (-3/2, -1) Slope: 8 Perpendicular slope: -1/8 Perpendicular bisector equation: y --1 = -1/8--3/2 => y = -1/8x -19/16

Yes, while naming a line segment, as long as the two points are on the line, it does not matter what order they are in or which points they are. well their not

The difference between defined and undefined terms is that the defined terms can be combined with each other and with undefined terms to define still more terms. These are undefined terms: 1.plane 2.point 3.line These are defined terms: 1.ray 2.union of sets 3.space 4.subset 5.set 6.proper subset 7.opposite rays 8.postulate 9.betweenness of points 10.bisector of a segment 11.midpoint of a segment 12.line segment 13.lenght of a segment 14.collinear points 15.complement of a set 16.coplanar points 17.disjoint sets 18.element 19.empy set 20.finite set 21.geometry 22.infinite set 23.intersection of sets

No they could not.

Related questions

If you mean endpoints of (16, 5) and (-6, -9) then its midpoint is (5, -2)

Endpoints: (-1, 3) and (-2, -5) Midpoint: (-3/2, -1) Slope: 8 Perpendicular slope: -1/8 Perpendicular bisector equation: y --1 = -1/8--3/2 => y = -1/8x -19/16

Yes, while naming a line segment, as long as the two points are on the line, it does not matter what order they are in or which points they are. well their not

midpoint between 4-16

midpoint between 4-16

8

Yes, because GB = GR - RB

Midpoint = (6+16)/2 and (6-6)/2 = (11, 0)

Endpoints: (3, 5) and (7,7) Midpoint: (5, 6) Slope: 1/2 Perpendicular slope: -2 Perpendicular bisector equation: y-6 = -2(x-5) => y = -2x+16

Midpoint = (3+7)/2, (5+7)/2 = (5, 6) Slope of line segment = 7-5 divided by 7-3 = 2/4 = 1/2 Slope of the perpendicular = -2 Equation of the perpendicular bisector: y-y1 = m(x-x1) y-6 =-2(x-5) y = -2x+10+6 Equation of the perpendicular bisector is: y = -2x+16

17.5

Because b is the mid point of pq, pb = qb. pb is half as long as pq Eq#1....pb = 1/2 pq Eq#2....pq = pb +8 Substitute Eq#1 into Eq #2 pq = 1/2 pq + 8 subtracting1/2 pq from both sides 1/2 pq = 8 pq = 16 problem here: you can't subtract 1/2 ... you would have to divide.

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