The answer will depend on where, in the sequence, the missing number is meant to be. Also, in each case, there are infinitely many possible answers since it is possible to find a polynomial of degree 5 (or higher) that will go through each of the above numbers and ANY other number, missing from ANY position.
Using polynomials of order 4, though, there is only one answer for each position. For example,
First number missing: 171
Un= (-27n4+ 422n3- 2364n2+ 5611n - 4668)/6
Last number missing: 218
Un= (-27n4+ 314n3- 1260n2+ 2041n - 1026)/6
The answer will depend on where, in the sequence, the missing number is meant to be. Also, in each case, there are infinitely many possible answers since it is possible to find a polynomial of degree 5 (or higher) that will go through each of the above numbers and ANY other number, missing from ANY position.
Using polynomials of order 4, though, there is only one answer for each position. For example,
First number missing: 171
Un= (-27n4+ 422n3- 2364n2+ 5611n - 4668)/6
Last number missing: 218
Un= (-27n4+ 314n3- 1260n2+ 2041n - 1026)/6
The answer will depend on where, in the sequence, the missing number is meant to be. Also, in each case, there are infinitely many possible answers since it is possible to find a polynomial of degree 5 (or higher) that will go through each of the above numbers and ANY other number, missing from ANY position.
Using polynomials of order 4, though, there is only one answer for each position. For example,
First number missing: 171
Un= (-27n4+ 422n3- 2364n2+ 5611n - 4668)/6
Last number missing: 218
Un= (-27n4+ 314n3- 1260n2+ 2041n - 1026)/6
The answer will depend on where, in the sequence, the missing number is meant to be. Also, in each case, there are infinitely many possible answers since it is possible to find a polynomial of degree 5 (or higher) that will go through each of the above numbers and ANY other number, missing from ANY position.
Using polynomials of order 4, though, there is only one answer for each position. For example,
First number missing: 171
Un= (-27n4+ 422n3- 2364n2+ 5611n - 4668)/6
Last number missing: 218
Un= (-27n4+ 314n3- 1260n2+ 2041n - 1026)/6
To find the missing number in the sequence 16, 4, 12, 36, 9, 27, 44, 11, we can look for a pattern. The first set of numbers appears to alternate between two sequences: the first sequence (16, 12, 9, 44) and the second sequence (4, 36, 27, 11). Following this pattern, the missing number, which follows the last number in the second sequence (11), should be 33. Thus, the missing number is 33.
The missing number is 18
The missing number in the series 1, 4, 27, 3125 can be identified by observing the pattern of powers. Each number corresponds to a base raised to an increasing exponent: (1^1), (2^2), (3^3), and (5^5). Therefore, the missing number, which corresponds to (4^4), is 256.
The sequence appears to be decreasing by 3, then increasing by 3. Following this pattern, starting from 33, if we subtract 3, we get 30. Thus, the missing number is 30. The complete sequence would be 33, 30, 24, 27.
I think your last number should be 216 as the others are the cubes of numbers 1, 2, 3 and 5. The missing number is 4 cubed, ie 64.
To find the missing number in the sequence 16, 4, 12, 36, 9, 27, 44, 11, we can look for a pattern. The first set of numbers appears to alternate between two sequences: the first sequence (16, 12, 9, 44) and the second sequence (4, 36, 27, 11). Following this pattern, the missing number, which follows the last number in the second sequence (11), should be 33. Thus, the missing number is 33.
If a progression goes 15 __ 21, then the missing number will dictate how the pattern increases with every number. If the missing number is 18, this means that the numbers go up in threes. The pattern would continue 24, 27, 30, 33...
The missing number is 18
The missing number in the series 1, 4, 27, 3125 can be identified by observing the pattern of powers. Each number corresponds to a base raised to an increasing exponent: (1^1), (2^2), (3^3), and (5^5). Therefore, the missing number, which corresponds to (4^4), is 256.
The sequence appears to be decreasing by 3, then increasing by 3. Following this pattern, starting from 33, if we subtract 3, we get 30. Thus, the missing number is 30. The complete sequence would be 33, 30, 24, 27.
I think your last number should be 216 as the others are the cubes of numbers 1, 2, 3 and 5. The missing number is 4 cubed, ie 64.
456445
33
The answer depends on where, within the sequence, the missing number should have been.
64
44 = 256
64 is missing; the numbers are cubes of 1,2,3,4,5,& 6.