4
If
1. x = y + 6 (which we can now re-write as y = x - 6)
2. y = -2 - x
We now want to do something which will eliminate either the x's or y's so that we only have one variable to worry about at a time.
If we add 1. & 2. together we will eliminate the x's as the x in 1. will cancel out with the -x in 2.
So 1. y = x -6 added to 2. y = -2 - x gives us:
3. 2y = -8
Thus y = -4
We now substitute the value of y back into either 1 or 2.
So substituting y = -4 into 1. gives us
-4 = x - 6
x = -4 + 6
x = 2.
Thus x = 2 and y = -4
Your ordered pair is therefore (2, -4).
(Note: to test we haven't made any errors here simply put both the values back in to 1. & 2. and check that the equations balance.)
(5,3)
{-4,-5}
x = -6 y = -11
There are an infinite number of ordered pairs. Any point on the straight line which passes through (0,4) and has a gradient of -2 will be an ordered pair for the equation.
x = 3 and y = 4 so the lines intersect at (3, 4)
The ordered pair is (1, 3).
k
(5,3)
The ordered pair is (-1, -2).
There are an infinite number of ordered pairs. (-5, -7) is one pair
{-4,-5}
x = -6 y = -11
There are an infinite number of ordered pairs. Any point on the straight line which passes through (0,4) and has a gradient of -2 will be an ordered pair for the equation.
x = 3 and y = 4 so the lines intersect at (3, 4)
y=(-1) x=(2)
2y + 2x = 20 y - 2x = 4 Add the two equations: 3y = 24 so that y = 8 Substitute this value of y in the second equation: 8 - 2x = 4 then 4 = 2x so that x = 2 Thus the ordered pair (y,x) = (8,2)
The ordered pair is (3, 2).