2
-log(1.2 X 10^-5 M H(+)) = 4.9 pH H(+)
pH means -log10(H+concentration) so pH of a H+ concentration 3.6x10-9 is: pH = -log10(3.6x10-9) ≈ 8.4
solution with [OH-] = 2.5 x 10-9 , A solution with [H+] = 1.2 x 10-4, A solution with pH = 4.5
-log(9.40 X 10^-4) = 3 pH
2
-log(1.2 X 10^-5 M H(+)) = 4.9 pH H(+)
pH means -log10(H+concentration) so pH of a H+ concentration 3.6x10-9 is: pH = -log10(3.6x10-9) ≈ 8.4
The pH of a solution is calculated using the formula pH = -log[H+]. Plugging in the given value of [H+] = 7.0x10^-7, you would get a pH of 6.15 for this solution.
solution with [OH-] = 2.5 x 10-9 , A solution with [H+] = 1.2 x 10-4, A solution with pH = 4.5
The pH of a solution with [H+] = 7.0 x 10^-2 is pH = -log(7.0 x 10^-2) = 1.15.
-log(9.40 X 10^-4) = 3 pH
apexvs answer 3.3
- log(2.3 X 10 -12 ) = 11.6 pH -----------------very little H + concentration in this solution.
The pH of a neutral solution with equal concentrations of H+ and OH- ions is 7. This is because the concentration of H+ ions equals the concentration of OH- ions in a neutral solution, resulting in a pH of 7.
The pH of a solution with a H+ concentration of 7.0 x 10^-2 M can be calculated using the formula pH = -log[H+]. In this case, pH = -log(7.0 x 10^-2) = 1.15.
pH = -log [H+], so if the [H+] is 2.310 M, the pH = -0.3636