22 meters
The perimeter (distance around the outside) = length + width + length + width
P = 2L + 2W
2 (8) + 2 (3) = 16 + 6 = 22
also:
P = 2 (L + W)
2(8 + 3) = 22
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(L + W) x 2 (8 + 3) x 2 = 11 x 2 = 22m
Perimeter is just twice the sum of length and width, in this case 2 x 11 m ie 22 m.
Perimeter = 33+33+3+3 = 72 m
Use Pythagoras' theorem:- 82+32 = 73 and the square root of this is length of the diagonal which is about 8.544m to 3 decimal places
That depends on the dimensions !... A 1 x 18 rectangle has a perimeter of 38 ! A 2 x 9 rectangle has a perimeter of 22 ! A 3 x 6 rectangle has a perimeter of 18 !