Endpoints: (s, 2s) and (3s, 8s)
Midpoint: (2s, 5s)
Slope of line: 3/1
Slope of perpendicular line: -1/3
Perpendicular bisector equation: y-5s = -1/3(x-2s) => 3y = -x+17s
Perpendicular bisector equation in its general form: x+3y-17s = 0
Endpoints: (-2, 4) and (6, 8) Slope: 1/2 Perpendicular slope: -2 Midpoint: (2, 6) Perpendicular bisector equation: y = -2x+10
Endpoints: (-1, -6) and (5, -8) Midpoint: (2, -7) Slope: -1/3 Perpendicular slope: 3 Perpendicular bisector equation: y - -7 = 3(x -2) => y = 3x -13
Endpoints: (s, 2s) and (3s, 8s) Midpoint: (2s, 5s) Slope: 3 Perpendicular slope: -1/3 Perpendicular bisector equation: 3y = -x+17s or as x+3y-17s = 0
Converse of the Perpendicular Bisector Theorem - if a point is equidistant from the endpoints of a segment, then it is on the perpendicular bisector of the segment.Example: If DA = DB, then point D lies on the perpendicular bisector of line segment AB.you :))
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Endpoints: (-2, 4) and (6, 8) Slope: 1/2 Perpendicular slope: -2 Midpoint: (2, 6) Perpendicular bisector equation: y = -2x+10
Endpoints: (2, 9) and (9, 2) Midpoint: (5.5, 5.5) Slope of line segment: -1 Perpendicular slope: 1 Perpendicular bisector equation: y-5.5 = 1(x-5.5) => y = x
Endpoints: (-1, -6) and (5, -8) Midpoint: (2, -7) Slope: -1/3 Perpendicular slope: 3 Perpendicular bisector equation: y - -7 = 3(x -2) => y = 3x -13
Endpoints: (-1, 3) and (-2, -5) Midpoint: (-3/2, -1) Slope: 8 Perpendicular slope: -1/8 Perpendicular bisector equation: y --1 = -1/8--3/2 => y = -1/8x -19/16
Endpoints: (s, 2s) and (3s, 8s) Midpoint: (2s, 5s) Slope: 3 Perpendicular slope: -1/3 Perpendicular bisector equation: 3y = -x+17s or as x+3y-17s = 0
Converse of the Perpendicular Bisector Theorem - if a point is equidistant from the endpoints of a segment, then it is on the perpendicular bisector of the segment.Example: If DA = DB, then point D lies on the perpendicular bisector of line segment AB.you :))
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The points on the perpendicular bisector of a segment are equidistant from the segment's endpoints. This means that if you take any point on the perpendicular bisector, it will be the same distance from both endpoints of the segment. Additionally, the perpendicular bisector is a line that divides the segment into two equal parts at a right angle.
The perpendicular bisector theorem states that if a point is on the perpendicular bisector of a line segment, then it is equidistant from the endpoints of that segment. Conversely, if a point is equidistant from the endpoints of a segment, it lies on the perpendicular bisector of that segment. This theorem is a fundamental concept in geometry, often used in constructions and proofs.
Every point in a plane that is equidistant from the endpoints of a segment lies on the perpendicular bisector of that segment. The perpendicular bisector is a line that is perpendicular to the segment and passes through its midpoint. Therefore, any point on this line will maintain equal distances to both endpoints of the segment.
The distance will be length of the line divided by 2 because the perpendicular bisector cuts through the line at its centre and at right angles
Endpoints: (-4, -10) and (8, -1) Midpoint: (2, -5.5) Slope: 3/4 Perpendicular slope: -4/3 Perpendicular equation: y --5.5 = -4/3(x-2) => 3y = -4x -8.5 Perpendicular bisector equation in its general form: 4x+3y+8.5 = 0