Points: (-3, 2) and (6, 8)
Slope: 2/3
Equation: y-2 = 2/3(x--3) => 3y = 2x+12
Both equations will intersect at (3, 6) when solved simultaneously
The point (3, 6).
Points of intersection work out as: (3, 4) and (-1, -2)
1st equation: 3x+2y = 2 2nd equation: x-3y = -14 Multiply all terms in the 2nd equation by 3 and subtract it from the 1st equation:- So: 11y = 44 or y = 4 By substitution point of intersection is at: (-2, 4)
No, in the Cartesian coordinate system it would show a vertical line whose intersection of the x-axis is 4.
False.
2
It works out that the point of intersection is at (-4, -3.5) on the Cartesian plane.
Points of intersection work out as: (3, 4) and (-1, -2)
8
It is the Cartesian equation of an ellipse.
It's possible
1st equation: 3x+2y = 2 2nd equation: x-3y = -14 Multiply all terms in the 2nd equation by 3 and subtract it from the 1st equation:- So: 11y = 44 or y = 4 By substitution point of intersection is at: (-2, 4)
No, in the Cartesian coordinate system it would show a vertical line whose intersection of the x-axis is 4.
Points of line: (13, 17) and (19, 23) Its slope: 1 Its equation: y = x+4 => y-x = 4 Multiply all terms by 4: 4y-4x = 16 Equation of: 4y = 5x => 4y-5x = 0 Subtacting equations: x = 16 By substitution point of intersection is at: (16, 20)
False.
2
It crosses the y axis at (0,6) and crosses the x axis at (-6,0). It is a straight line with a positive slope.
The second