5 independent events, each of them with a probability of 1/2; you need to multiply all together, so you get (1/2) to the power 5.Note: any other specific combination you can get when throwing a coin 5 times - for example, head, tails, head, tails, head - will have the same probability.
Since zero is not on the die, the probability of getting a zero is 0%.
On a single roll of a normal die the probability of getting a 7 is 0.
The probability of getting 8 heads out of 10 tosses is (10C8)(1/2)^8 (1/2)^2 = 45 / 1024 = 0.0439. It is assumed that the probability of getting a head in a single toss is 1/2. 10C8 = 10 x 9 / 1 x 2 = 45
It is 1/6.
It is 0.5
the probability of tossing a coin and it landing on head is a 1 in 2 chance the probability of rolling a 5 on a dice is a 1 in 6 chance
The probability is 0. Consider the event of tossing a coin . The possible events are occurrence of head and tail. they are mutually exclusive events. Hence the probability of getting both the head and tail in a single trial is 0.
The probability of getting an odd number in a single throw of a fair die (not dice!) is 1/2.The probability of getting an odd number in a single throw of a fair die (not dice!) is 1/2.The probability of getting an odd number in a single throw of a fair die (not dice!) is 1/2.The probability of getting an odd number in a single throw of a fair die (not dice!) is 1/2.
Since zero is not on the die, the probability of getting a zero is 0%.
The probability of rolling a 7 at any time on a single die is zero.
1:6
the probability is 2/6
On a single roll of a normal die the probability of getting a 7 is 0.
total outcome in single toss={H,T} u want 1 head probability of getting 1 head= 1/2=0.5
The probability of getting 8 heads out of 10 tosses is (10C8)(1/2)^8 (1/2)^2 = 45 / 1024 = 0.0439. It is assumed that the probability of getting a head in a single toss is 1/2. 10C8 = 10 x 9 / 1 x 2 = 45
.33333333333333333
1/6