It is 1/3.
It is 1/3.
It is 1/3.
It is 1/3.
It is 1/3.
The multiples of 3 that can be rolled are 3 and 6 Therefore probability of a success is 2/6 or 1/3
The favourable outcomes are 1, 3, 5 or 6 so the probability is 4/6 = 2/3
There are two multiples of three on a die and there are six possible outcomes. So, the probability is 2/6 = 1/3 = 0.3333 or 33.33%
The probability of getting a multiple of 3 depends on the total number of possible outcomes. For example, if you are rolling a fair six-sided die, there are two outcomes that are multiples of 3 (3 and 6), out of a total of six possible outcomes. Therefore, the probability of getting a multiple of 3 is 2/6 or 1/3.
Assuming an unbiased die, there are six possible outcomes with equal probability {1, 2, 3, 4, 5, 6}. Of these six possibilities three of them, namely {2, 4, 6}, are divisible by 2. Probability = number_of_successful_outcomes/total_number_of_outcomes = 3/6 = 1/2
The probability that you roll a multiple of 3 (3 and 6) in a fair die is: P(3 or 6) = 2/6=1/3 = 0.333... ≈ 33.3%.The probability that you roll a multiple of 5 (5) is: P(5) = 1/6.The probability that you roll a multiple of 3 or 5 is: P(3 or 6 or 5) = 2/6 + 1/6 = 1/2 = 0.50 = 50%
When you roll a 6 sided die there are 6 possible outcomes. 1,2,3,4,5,6. Out of these 3 are multiples of 2. Therefore the Probability of getting a multiple of 2 is (3/6) which simplifies to (1/2) or a half.
It is 1/6.
one die has 6 numbers or sides, 3 of which are multiples of 2 (2,4,6) and 3 of which are not (1,3,5). so the odds of not rolling a multiple of 2 are: 3 in 6, simplified to 1 in 2, also known as 50%
The multiples of 3 that can be rolled are 3 and 6 Therefore probability of a success is 2/6 or 1/3
2/6 It should be 3/6. Because the sample space is S=(1,2,3,4,5,6) As 2,4 and 6 is a multiple of 2, it should be 3/6
The favourable outcomes are 1, 3, 5 or 6 so the probability is 4/6 = 2/3
I am not sure but I think 3/36
There are two multiples of three on a die and there are six possible outcomes. So, the probability is 2/6 = 1/3 = 0.3333 or 33.33%
The probability of correct true & false question is 1/2 and the probability correct multiple choice (four answer) question is 1/4. We want the probability of correct, correct, and correct. Therefore the probability all 3 questions correct is 1/2 * 1/2 * 1/4 = 1/16.
The probability of getting a multiple of 3 depends on the total number of possible outcomes. For example, if you are rolling a fair six-sided die, there are two outcomes that are multiples of 3 (3 and 6), out of a total of six possible outcomes. Therefore, the probability of getting a multiple of 3 is 2/6 or 1/3.
Assuming an unbiased die, there are six possible outcomes with equal probability {1, 2, 3, 4, 5, 6}. Of these six possibilities three of them, namely {2, 4, 6}, are divisible by 2. Probability = number_of_successful_outcomes/total_number_of_outcomes = 3/6 = 1/2