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If John throws a fair 6 sided die what is the probability he will get a multiple of 3?
The multiples of 3 that can be rolled are 3 and 6 Therefore probability of a success is 2/6 or 1/3
What is the probability of getting an odd number or a multiple of 3 when an unbiased die is tossed once?
The favourable outcomes are 1, 3, 5 or 6 so the probability is 4/6 = 2/3
What is the probability of rolling a number that is a multiple of 3 on a die?
There are two multiples of three on a die and there are six possible outcomes. So, the probability is 2/6 = 1/3 = 0.3333 or 33.33%
What is the probability of getting a multiple of 3?
The answer depends on the domain. If the selection is made from any real or rational numbers, the probability is 0. If the domain is all integers (or all positive integers) then the probability is 1/3. If it is some other subset of integers, then the answer is a rational number between 0 and 1/3.
What is the probability of rolling a multiple of 2 on a six sided die?
Assuming an unbiased die, there are six possible outcomes with equal probability {1, 2, 3, 4, 5, 6}. Of these six possibilities three of them, namely {2, 4, 6}, are divisible by 2. Probability = number_of_successful_outcomes/total_number_of_outcomes = 3/6 = 1/2
What is the probability of that you roll a multiple of 3 or 5 on a number cube?
The probability that you roll a multiple of 3 (3 and 6) in a fair die is: P(3 or 6) = 2/6=1/3 = 0.333... ≈ 33.3%.The probability that you roll a multiple of 5 (5) is: P(5) = 1/6.The probability that you roll a multiple of 3 or 5 is: P(3 or 6 or 5) = 2/6 + 1/6 = 1/2 = 0.50 = 50%
What is the probability of getting a multiple of 2 when you roll a 6 sided die?
When you roll a 6 sided die there are 6 possible outcomes. 1,2,3,4,5,6. Out of these 3 are multiples of 2. Therefore the Probability of getting a multiple of 2 is (3/6) which simplifies to (1/2) or a half.
What is the probability of rolling a sum that is a common multiple of 2 and 3 on 2 number cubes?
It is 1/6.
Suppose you roll one die Find the probability of not rolling a multiple of 2?
one die has 6 numbers or sides, 3 of which are multiples of 2 (2,4,6) and 3 of which are not (1,3,5). so the odds of not rolling a multiple of 2 are: 3 in 6, simplified to 1 in 2, also known as 50%
If John throws a fair 6 sided die what is the probability he will get a multiple of 3?
The multiples of 3 that can be rolled are 3 and 6 Therefore probability of a success is 2/6 or 1/3
Probability of getting a multiple of 2 on a die?
2/6 It should be 3/6. Because the sample space is S=(1,2,3,4,5,6) As 2,4 and 6 is a multiple of 2, it should be 3/6
What is the probability of getting an odd number or a multiple of 3 when an unbiased die is tossed once?
The favourable outcomes are 1, 3, 5 or 6 so the probability is 4/6 = 2/3
When two number cubes are rolled what is the probability that their sum will be a common multiple of 2 and 3?
I am not sure but I think 3/36
What is the probability of rolling a number that is a multiple of 3 on a die?
There are two multiples of three on a die and there are six possible outcomes. So, the probability is 2/6 = 1/3 = 0.3333 or 33.33%
Students are required to answer 2 True of False questions and 1 multiple choice questions with 4 responses If the answers are all guesses what is the probability of getting all 3 questions correct?
The probability of correct true & false question is 1/2 and the probability correct multiple choice (four answer) question is 1/4. We want the probability of correct, correct, and correct. Therefore the probability all 3 questions correct is 1/2 * 1/2 * 1/4 = 1/16.
What is the probability of getting a multiple of 3?
The answer depends on the domain. If the selection is made from any real or rational numbers, the probability is 0. If the domain is all integers (or all positive integers) then the probability is 1/3. If it is some other subset of integers, then the answer is a rational number between 0 and 1/3.
What is the probability of rolling a multiple of 2 on a six sided die?
Assuming an unbiased die, there are six possible outcomes with equal probability {1, 2, 3, 4, 5, 6}. Of these six possibilities three of them, namely {2, 4, 6}, are divisible by 2. Probability = number_of_successful_outcomes/total_number_of_outcomes = 3/6 = 1/2
