It is 1/3.
It is 1/3.
It is 1/3.
It is 1/3.
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The multiples of 3 that can be rolled are 3 and 6 Therefore probability of a success is 2/6 or 1/3
The favourable outcomes are 1, 3, 5 or 6 so the probability is 4/6 = 2/3
There are two multiples of three on a die and there are six possible outcomes. So, the probability is 2/6 = 1/3 = 0.3333 or 33.33%
The answer depends on the domain. If the selection is made from any real or rational numbers, the probability is 0. If the domain is all integers (or all positive integers) then the probability is 1/3. If it is some other subset of integers, then the answer is a rational number between 0 and 1/3.
Assuming an unbiased die, there are six possible outcomes with equal probability {1, 2, 3, 4, 5, 6}. Of these six possibilities three of them, namely {2, 4, 6}, are divisible by 2. Probability = number_of_successful_outcomes/total_number_of_outcomes = 3/6 = 1/2