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If he's rolling a conventional 6-sided number cube (and it's fair), that's 5 out of 6.

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That depends what numbers he can choose from.

Q: What is the probability that he gets a number greater than 3 or prime number?

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207 is not a prime number because it gets divided by 3.

A prime number only has two factors: itself and the number one. You get the prime number, your opponent gets one.

Probability is a number in the range [0, 1]. The question gives a probability (240) which is way outside this range and so is not valid.

Because a prime number only has two factors: one and the number itself.

It is: 1 times 29 = 29 which is a prime number

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The possible prime numbers are 2, 3, 5 The possible numbers greater than 3 are 4, 5, 6 → a success is 2 3, 4, 5, 6 → pr(prime or > 3) = 5/6

5-6

207 is not a prime number because it gets divided by 3.

A prime number has two factors: one and the number itself. When you circle a prime number, you get points for the number, your opponent gets points for the other factor, which is one. 23 is a prime number. You get 23, your opponent gets one. 37 is a prime number. You get 37 points, your opponent gets one.

A prime number only has two factors: itself and the number one. You get the prime number, your opponent gets one.

Probability is a number in the range [0, 1]. The question gives a probability (240) which is way outside this range and so is not valid.

Because a prime number only has two factors: one and the number itself.

No. For example, reversing 23 gets 32.

Yes, you can easily divide the number up to that number. If it gets divided by someone other than itself and 1, it is not prime.

It is: 1 times 29 = 29 which is a prime number

Let's assume you're talking about the factor game. Prime numbers only have two factors, themselves and one. You get the prime number, your opponent gets one.

If you are playing the factor game, the best move is usually the highest available prime number. Prime numbers have two factors. You get the number, your opponent gets 1.