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There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes.

However, if you assume that they are independent events then, given that the probability of a girl is approx 0.48, then

Prob(at least one girl out of 6 children) = 1 - Prob(no girls out of 6 children)

= 1 - Prob(6 boys out of 6 children)

= 1 - 0.526 = 0.9809

There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes.

However, if you assume that they are independent events then, given that the probability of a girl is approx 0.48, then

Prob(at least one girl out of 6 children) = 1 - Prob(no girls out of 6 children)

= 1 - Prob(6 boys out of 6 children)

= 1 - 0.526 = 0.9809

There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes.

However, if you assume that they are independent events then, given that the probability of a girl is approx 0.48, then

Prob(at least one girl out of 6 children) = 1 - Prob(no girls out of 6 children)

= 1 - Prob(6 boys out of 6 children)

= 1 - 0.526 = 0.9809

There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes.

However, if you assume that they are independent events then, given that the probability of a girl is approx 0.48, then

Prob(at least one girl out of 6 children) = 1 - Prob(no girls out of 6 children)

= 1 - Prob(6 boys out of 6 children)

= 1 - 0.526 = 0.9809

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