-10
(-8) x (-2) = 16 (-8) + (-2) = -10 The two numbers are therefore -8 and -2.
The sum of 9 and the product of 8 is calculated by first finding the product of 8, which is 8. Then, adding 9 to this product results in a sum of 17. Therefore, the sum of 9 and the product of 8 is 17.
3+ x/ 2
Let the consecutive integers be 'n' & 'n+1'. Their product is n(n+1) Their sum is n + n+ 1 = 2n + 1 Eight timres the sum is 8(2n+1) Their product being 8 less that their sum is n(n+1) = 8(2n+1) - 8 Hence n^(2) + n = 16n + 8 - 8 n^(2) + n = 16n n^(2) = 15n ( Cancel down by 'n'). n = 15 n+1 = 16 Hence '15' & '16' are the two numbers.
If you mean what numbers produce a product of 40 and a sum of 17, let me try. 2 x 2 x 2 x 5 x 1 x 1 x 1 x 1 = 40. 2+2+2+5+1+1+1+1=17. If you want the product of 40 and sum of 17 I think that means 40 X (17), which is 68.
8 + 3 = 11 8 x 3 = 24 The two numbers are therefore 8 and 3.
8*(x + 3)
(7 x 8) + (8 x 8) = 15 x 8 = 120
(-8) x (-2) = 16 (-8) + (-2) = -10 The two numbers are therefore -8 and -2.
The numbers 4 and 8 (4 x 8 = 32) sum to 12. The numbers 2 and 16 (2 x 16 = 32) sum to 18. There are no other factors which are integers, so 4 and 8 is the answer.
The two numbers with the sum of 15 and the product of 56 are: 7 + 8 = 15 7 x 8 = 56
The two numbers with a sum of 33 and a product of 200 are 25 and 8. 25 x 8 = 200, 25 + 8 = 33.
The sum of 9 and the product of 8 is calculated by first finding the product of 8, which is 8. Then, adding 9 to this product results in a sum of 17. Therefore, the sum of 9 and the product of 8 is 17.
3+ x/ 2
2(24 + 7) = (2 x 24) + 2 x 7) = 2 x 31 = 62
NO
8(3 + 5) = (8 x 3) + (8 x 5) = 8 x 8 = 64