If x is the lower integer then: x(x + 1) = 8 (x + x + 1) - 8
ie x2 + x = 16x + 8 - 8
ie x2 = 15x
ie x = 15
15 x 16 = 240; 8 x (15 + 16) = 8 x 31 = 248
Bingo!
The product of four consecutive integers is always one less than a perfect square. The product of four consecutive integers starting with n will be one less than the square of n2 + 3n + 1
The 3 consecutive odd positive integers are 7, 9 and 11.
They are 6, 8, 10 and 12.
The let statement is: let the smallest of the three integers be x.
It can be.
The integers are 5 and 7.
The product of four consecutive integers is always one less than a perfect square. The product of four consecutive integers starting with n will be one less than the square of n2 + 3n + 1
The 3 consecutive odd positive integers are 7, 9 and 11.
The numbers are 11, 13, 15 and 17.
They are 6, 8, 10 and 12.
4,6,8,10
Two consecutive integers will be 0.5 more and 0.5 less than the quotient of their sum divided by 2. The given sum of the two consecutive integers divided by 2 is -3471.5, so the two consecutive integers are -3472 and -3471.
The let statement is: let the smallest of the three integers be x.
Translate this phrase into an algebraic equation The product of two consecutive multiple of three integers?
The answer would be 10 12 and 14... 14 x 3 = 42 and 2(10 + 12) = 44. So the product of the largest integer and three is two less than twice the sum of the lower integers.
11, 13, 15 and 17(143 is 112 less than 255)The equation is (A)(A+2) = (A+4)(A+6) - 112A2 + 2A = A2 +10A +24 -1122A = 10A - 888A = 88A = 112,5,6
It can be.