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the product of -1 and an integer is 0 . the integer is

Q: What is the product of an integer and 0?

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The product would be a positive integer.

True. In general, the product is not an integer.

A negative integer multiplied by a negative integer is always a positive integer product. -x * -y = xy

In mathematics, a multiple of an integer is the product of that integer with another integer. In other words, a is a multiple of b if a = nb, where nis an integer. If b is not zero, this is equivalent to saying that a / b is an integer.0 is a multiple of every integer ().Source: http://en.wikipedia.org/wiki/Multiple_(mathematics)

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2

The product would be a positive integer.

True. In general, the product is not an integer.

Yes. The product of a negative integer and a positive integer is a negative integer.

A negative integer multiplied by a negative integer is always a positive integer product. -x * -y = xy

Zero is an integer.

-- The product is an integer. -- If the original two integers are both positive, then the product is positive. -- If the original two integers have different signs, then the product is negative.

In mathematics, a multiple of an integer is the product of that integer with another integer. In other words, a is a multiple of b if a = nb, where nis an integer. If b is not zero, this is equivalent to saying that a / b is an integer.0 is a multiple of every integer ().Source: http://en.wikipedia.org/wiki/Multiple_(mathematics)

negative integer

let this integer be (xy) (xy) = 10x + y 10x+y = 2.x.y 10x + y - 2xy = 0 2x.(5-y) +y= 0 x= y / 2(y-5) when the integer provides this condition, it is equal to twice the product of its digits. And there is such only one integer. 36

The statement is not true. Disprove by counter-example: 3 is an integer and 5 is an integer, their product is 15 which is odd.

It is not possible to have the product of an integer. "product" is a binary operation and that means that it is an operation that combines two numbers to make the product - a third number. So you need two numbers as input, not just one.