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# What is the rule for 1 2 6 24?

Updated: 9/23/2023

Wiki User

10y ago

There are infinitely many possible answers.

One such is Un = (11n3 - 57n2 + 100n - 48)/6 for n = 1, 2, 3, ...

A more likely one though, is Un = n! = n*(n-1)*...*2*1

There are infinitely many possible answers.

One such is Un = (11n3 - 57n2 + 100n - 48)/6 for n = 1, 2, 3, ...

A more likely one though, is Un = n! = n*(n-1)*...*2*1

There are infinitely many possible answers.

One such is Un = (11n3 - 57n2 + 100n - 48)/6 for n = 1, 2, 3, ...

A more likely one though, is Un = n! = n*(n-1)*...*2*1

There are infinitely many possible answers.

One such is Un = (11n3 - 57n2 + 100n - 48)/6 for n = 1, 2, 3, ...

A more likely one though, is Un = n! = n*(n-1)*...*2*1

Wiki User

10y ago

Wiki User

10y ago

There are infinitely many possible answers.

One such is Un = (11n3 - 57n2 + 100n - 48)/6 for n = 1, 2, 3, ...

A more likely one though, is Un = n! = n*(n-1)*...*2*1

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Q: What is the rule for 1 2 6 24?
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