There are infinitely many possible rules that can be used to generate the 7 number sequence given in the question.
One such is Un = (4n6 - 102n5 + 1015n4 - 4980n3 + 12511n2 - 14928n + 6720)/60 for n = 1 , 2, 3, ...
There are infinitely many possible rules that can be used to generate the 7 number sequence given in the question.
One such is Un = (4n6 - 102n5 + 1015n4 - 4980n3 + 12511n2 - 14928n + 6720)/60 for n = 1 , 2, 3, ...
There are infinitely many possible rules that can be used to generate the 7 number sequence given in the question.
One such is Un = (4n6 - 102n5 + 1015n4 - 4980n3 + 12511n2 - 14928n + 6720)/60 for n = 1 , 2, 3, ...
There are infinitely many possible rules that can be used to generate the 7 number sequence given in the question.
One such is Un = (4n6 - 102n5 + 1015n4 - 4980n3 + 12511n2 - 14928n + 6720)/60 for n = 1 , 2, 3, ...
1, 4, 7, 10, 13, …
The lucas numbers are a sequence of numbers. They go as 1, 3, 4, 7, 11, 18 etc the sequence is bery similar to the Fibonacci sequence (1, 1, 2, 3, 5, 8, 13)
Continuing the sequence would be the the numbers 24, 31, 39.
The series alternates between two sequences: one that increases by 1 (11, 12, 13, 14) and another that increases by 1 as well but starts from 2 (2, 3, 4). Following this pattern, the next number in the increasing sequence would be 15, and the next number in the second sequence would be 5. Therefore, the next numbers in the series would be 15 and 5.
Often when given only a few numbers in a sequence or series, there is more than one possible answer. As a sequence, this could be the numbers NOT divisible by 4. In this case the sequence is 1, 2, 3, 5, 6, 7, 9, 10, 11, 13, 14, 15, 17, 18, 19, 21, 22, 23, 25, 26, 27, 29, 30, 31, 33, 34, 35, 37, 38, 39, 41,... The sequence could be: all numbers n such that 2n + 9 is prime, or it could be all numbers n such that 30(n)+13 is prime, just to name a few.
This sequence is an arithmetic series that makes use of another series. This sequence advances by adding the series 4, 11, 21, 34, and 50 to the initial terms. This secondary series has a difference of 7, 10, 13 and 16 which advance by terms of 3. So the next three numbers in the primary sequence are 190, 281 and 397.
10 (between 7 and 13)
1, 4, 7, 10, 13, …
6 and 10
The lucas numbers are a sequence of numbers. They go as 1, 3, 4, 7, 11, 18 etc the sequence is bery similar to the Fibonacci sequence (1, 1, 2, 3, 5, 8, 13)
1, 1, 2, 4, 7, 13, 24, 44... You add the last 3 numbers of the sequence together.
Continuing the sequence would be the the numbers 24, 31, 39.
Dart Board
The series alternates between two sequences: one that increases by 1 (11, 12, 13, 14) and another that increases by 1 as well but starts from 2 (2, 3, 4). Following this pattern, the next number in the increasing sequence would be 15, and the next number in the second sequence would be 5. Therefore, the next numbers in the series would be 15 and 5.
Often when given only a few numbers in a sequence or series, there is more than one possible answer. As a sequence, this could be the numbers NOT divisible by 4. In this case the sequence is 1, 2, 3, 5, 6, 7, 9, 10, 11, 13, 14, 15, 17, 18, 19, 21, 22, 23, 25, 26, 27, 29, 30, 31, 33, 34, 35, 37, 38, 39, 41,... The sequence could be: all numbers n such that 2n + 9 is prime, or it could be all numbers n such that 30(n)+13 is prime, just to name a few.
364
The next number is 47. After this series gets going, each number is the sum of the two numbers before it. If the first two numbers were zero and 1, this would be the Fibonacci series.